我在使用查询构建器删除 id 找到的所有记录时遇到了一些麻烦,我尝试过像下面的代码一样,但我总是收到这个错误:
[Semantical Error] line 0, col 53 near 'b.id = :surv': Error: 'b' is not defined.
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方法:
public function deleteUsers($surveyId) {
$qb = $this->getEntityManager()->createQueryBuilder();
return $qb
->delete()
->from(BaseUser::class, 'a')
->leftJoin('a.survey', 'b')
->where('b.id = :survey')
->setParameter('survey', $surveyId)
->getQuery()
->execute()
;
}
Run Code Online (Sandbox Code Playgroud) 鉴于以下表单类型,我如何在提交之前呈现我的第二个字段?我试过了,$form->remove但我总是会收到这个错误:
Warning: Illegal offset type in isset or empty
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不太确定如何解决这个问题。
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('survey', EntityType::class, [
'class' => SurveyManager::class,
'attr' => [
'class' => 'field-change',
],
])
->add('submit', SubmitType::class, [
])
->addEventListener(
FormEvents::PRE_SUBMIT,
function (FormEvent $event) {
$form = $event->getForm();
$data = $event->getData();
$modifier = $data['survey'];
$form->add('headquarter', EntityType::class, [
'class' => HeadQuarterManager::class,
'query_builder' => function (HeadQuarterManagerRepository $er) use ($modifier) {
return $er->getHeadquarter($modifier);
}, …Run Code Online (Sandbox Code Playgroud)