粗粒度和细粒度之间有什么区别？

我在谷歌搜索过这些术语,但我找不到他们的意思.

我想比较num和{{buildSummary_list.number}},但为什么它不起作用？我收到了一个错误

Could not parse the remainder: '{{buildSummary_list.number}}' from '{{buildSummary_list.number}}'"...

{% for num in buildSummary_list.paginator.page_range %}
    {% ifequal num {{buildSummary_list.number}} %}
        <b>{{num}}</b>
    {% endifequal %}
    {% ifnotequal num {{buildSummary_list.number}} %}
        <a href="?page={{num}}"><b>{{num}}</b></a>
    {% endifnotequal %}

{% endfor %}

我想让分页有效:前<< 1 2 3 4 5 6 >>下

我的代码可以运行,它可以产生这种效果吗？感谢:D

当我调用runDelete时,它会调用run,那么为什么"view没有返回一个HttpResponse对象"呢？

谢谢:)

views.py

def run(request, build):
    run_list = []   
    target_dict = {}
    target_num = 0
    build_id = 0
    all_run_list = TestRun.objects.all().order_by('id')
    for run in all_run_list:
        build_version = run.build.version
        build_number = run.build.number
        run_build = build_version + '.' + build_number
        if (build==run_build):
            run_list.append(run)
    return render_to_response('run.html', {'run_list': run_list})

def runDelete(request):
    run_list = request.POST.getlist('var_delete')
    build_id = request.POST.get('build_id')
    for run2 in run_list:
        run2 = int(run2)
    build_id = int(build_id)
    build_obj = Build.objects.get(id=build_id)
    build_version = build_obj.version
    build_number = build_obj.number
    build = build_version + '.' + …

我有一个由Visual Studio 2010运行的C++程序,如何监视程序的内存使用情况？是否存在简单的API,例如我可以调用clock_t start1和start1 = clock();监视程序的时间使用情况.谢谢:)

我想存储10个Obj对象objList,但我不知道delete在这种情况下何时适当使用.如果我delete Obj;在下面代码中注明的行中使用,是否Obj仍然存储objList？

struct Obj {
    int u;
    int v;
};

vector<Obj> objList;

int main() {
    for(int i = 0; i < 10; i++) {
        Obj *obj = new Obj();
        obj->u = i;
        obj->v = i + 1;
        objList.push_back(*obj);
        // Should i use "delete Obj;" here? 
    }
}

我尝试将hibernate与PostgreSQL连接,但我不知道为什么它不起作用.我搜索过很多关于这个设置的帖子,但它们并不适合我.非常感谢你!

以下是我的文件结构:

的hibernate.cfg.xml

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-configuration SYSTEM 
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
   <session-factory>
   <property name="hibernate.dialect">
      org.hibernate.dialect.PostgreSQLDialect
   </property>
   <property name="hibernate.connection.driver_class">
      org.postgresql.Driver
   </property>
   <property name="hibernate.connection.url">
      jdbc:postgresql://localhost:5432/hibernatedb
   </property>
   <property name="hibernate.connection.username">
      eric
   </property>
   <property name="hibernate.connection.password">
      eric123
   </property>

   <mapping resource="Employee.hbm.xml"/>
</session-factory>
</hibernate-configuration>

Employee.hbm.xml

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC 
 "-//Hibernate/Hibernate Mapping DTD//EN"
 "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd"> 

<hibernate-mapping>
   <class name="Employee" table="EMPLOYEE">
      <meta attribute="class-description">
         This class contains the employee detail. 
      </meta>
      <id name="id" type="int" column="id">
         <generator class="native"/>
      </id>
      <property name="firstName" column="first_name" type="string"/>
      <property name="lastName" column="last_name" type="string"/>
      <property name="salary" column="salary" type="int"/>
   </class> …

import java.util.*;

public class test4 {
  public static void main(String[] args){
    PriorityQueue[] P = new PriorityQueue[10];
    P[1] = new PriorityQueue<ClassEntry>();
    P[1].add(new ClassEntry(1.2,1));
    P[1].add(new ClassEntry(1.5,2));
    P[1].add(new ClassEntry(1.2,3));
    P[1].add(new ClassEntry(10,4));

    P[1].remove(new ClassEntry(10,4));//I can't delete this object???

    System.out.println(P[1].size());
    ClassEntry ce = (ClassEntry) P[1].peek();
    System.out.println(P[1].size());
    System.out.println(ce.sim+"\t"+ce.index);
  }
}

为什么我不能删除 (10,4)？有人可以教如何实施...谢谢！

我name1用Spring + Hibernate 编写了一个postgresql并从我的java代码中传递参数.

SELECT * FROM Test
WHERE name = COALESCE(:name1, name2)

但是我得到了一个错误

ERROR: COALESCE types bytea and character varying

name1我的java代码中的String 类型.

我试图解决这个问题

COALESCE(convert_from(:name1,'UTF8'), name2)

它将在Eclipse中通过JUNIT Test.但是,当我在Tomcat上运行它时,我会收到错误

Error:convert_from(character varying, unknown) not exist

怎么解决？谢谢.

我有一个.csv文件,格式如下所示:

mapping.csv

5188.40811,TMobileML
5131.40903,TMobileGregsapt
5119.40791,TMobileJonsapartment
5123.40762,TMobileRedhat

我想将它存储在一个4乘2的数组中,当我有一个值(例如5131.40903'这是一个'字符串'而不是'int')时,我想找到映射关系TMobileGregsapt.但我遇到两个问题,第一个是我不能使用csvread('mapping.csv'),它会有一些错误:(我认为问题可能5131.40903是int当我使用csvread,但是TMobileGregsapt是一个字符串...)

??? Error using ==> dlmread at 145
Mismatch between file and format string.
Trouble reading number from file (row 1, field 2) ==> TMobi

Error in ==> csvread at 52
    m=dlmread(filename, ',', r, c);

即使我使用dlmread('cell4.csv', ','),它仍然有一些错误:

??? Error using ==> dlmread at 145
Mismatch between file and format string.
Trouble reading number from file (row 1, field 2) ==> …

我想使用multer从表单上传快照上传图像.

我找到一篇关于如何使用multer上传文件,并触发事件来重命名文件的帖子.但是,我发现它只适用于旧版本(multer-0.1.6)

在multer的github中的最新指令中,我认为我必须使用disk storage engine新名称上传文件,但它不起作用.请给我一些指示,我整天都试过这个功能......

而且,我不确定为什么res.status(204).end();需要？我不添加这一行,当我点击上传按钮时网页总会锁定...

的package.json

{
  "name": "FileUpload",
  "version": "0.0.0",
  "private": true,
  "scripts": {
    "start": "node ./bin/www"
  },
  "dependencies": {
    "body-parser": "~1.13.2",
    "cookie-parser": "~1.3.5",
    "debug": "~2.2.0",
    "express": "~4.13.1",
    "jade": "~1.11.0",
    "morgan": "~1.6.1",
    "multer": "^1.0.6",
    "serve-favicon": "~2.3.0"
  }
}

upload.js

var express = require('express');
var multer  = require('multer');
var upload = multer({ storage: storage });

var app = express();

app.post('/uploadImage', upload.single('image'), function (req, res, next) {
    console.log("success");
    console.log(req.file);
    res.status(204).end();
});

app.get('/',function(req,res){ …