小编Kul*_*ngh的帖子

查询1：

byte a = 0; // int to byte implicit conversion happens, correct!, no CTE [compile time error]
setByte(0); // CTE!, why ? implicit conversion do not happen here 
void setByte(byte b){}

查询2：

byte b_byte = 128 - 1; // integer literal computation results to 127 int which implicitly casts to byte and as 127 is in range of byte so no CTE, Correct!
int a_int = 2147483647; // in range of int, so no CTE
int b_int = 2147483648 …

鉴于我有以下功能

static void fun(String str) {
        System.out.println(String.format("%s | length in String: %d | length in bytes: %d | bytes: %s", str, str.length(), str.getBytes().length, Arrays.toString(str.getBytes())));
    }

调用fun("ó");它的输出是

ó | length in String: 1 | length in bytes: 2 | bytes: [-61, -77]

所以这意味着字符 ó 需要 2 个字节来表示，并且根据 Character 类文档，Java 中的默认值也是 UTF-16，考虑到当我执行以下操作时

System.out.println(new String("ó".getBytes(), StandardCharsets.UTF_16));// output=?
System.out.println(new String("ó".getBytes(), StandardCharsets.ISO_8859_1));// output=ó
System.out.println(new String("ó".getBytes(), StandardCharsets.US_ASCII));// output=??
System.out.println(new String("ó".getBytes(), StandardCharsets.UTF_8));// output=ó
System.out.println(new String("ó".getBytes(), StandardCharsets.UTF_16BE));// output=?
System.out.println(new String("ó".getBytes(), StandardCharsets.UTF_16LE));// output=?

为什么任何 UTF_16、UTF_16BE、UTF_16LE 字符集都无法正确解码字节，因为字节代表 16 …