我试着写一个正则表达式来匹配10或12位数的组合.喜欢:
1234567890 - 真
123456789012 - 真
12345678901 - 假
123456-假
1234567890123-错误
仅匹配10或12位数.我试过这个:
"^[0-9]{10}|[0-9]{12}$"
Run Code Online (Sandbox Code Playgroud) 根据此报告定义,如何更改PDF中使用的文件名,以便使用"SO-001.pdf"等名称.
<report
id = "report_custom_sale_order"
string = "Quotation / Order"
model = "sale.order"
report_type = "qweb-pdf"
file = "custom_saleorder.report_saleorder"
name = "custom_saleorder.report_saleorder"
paperformat = "custom_saleorder.paperformat_a4"
/>
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Odoo 10.
谢谢
在我的自定义模块中,我添加了
application_no = fields.Char(string="Application Number")
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_sql_constraints = [
('application_no_unique',
'UNIQUE(application_no)',
"Application Number already exist.Please specify another number or make sure the application number is correct"),
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]
我使用sql约束来显示警告.
它工作正常,当我们输入重复的应用程序编号时,它会显示警告并阻止保存记录的访问权限
题
警告发生时如何保存记录?
注意
我认为SQL约束不适合这个.是这个功能的任何其他方法?
我想在Python中构建一个基于内容的推荐系统,它使用多个属性来决定两个项是否相似.在我的例子中,"items"是由C#包管理器(示例)托管的包,它们具有各种属性,例如名称,描述,标签,可以帮助识别类似的包.
我这里有一个原型推荐系统,目前只使用一个属性,描述来决定包是否相似.它计算了描述的TF-IDF排名,并根据以下内容打印出前10项建议:
# Code mostly stolen from http://blog.untrod.com/2016/06/simple-similar-products-recommendation-engine-in-python.html
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def train(dataframe):
tfidf = TfidfVectorizer(analyzer='word',
ngram_range=(1, 3),
min_df=0,
stop_words='english')
tfidf_matrix = tfidf.fit_transform(dataframe['description'])
cosine_similarities = linear_kernel(tfidf_matrix, tfidf_matrix)
for idx, row in dataframe.iterrows():
similar_indices = cosine_similarities[idx].argsort()[:-10:-1]
similar_items = [(dataframe['id'][i], cosine_similarities[idx][i])
for i in similar_indices]
id = row['id']
similar_items = [it for it in similar_items if it[0] != id]
# This 'sum' is turns a list of tuples into a single tuple:
# [(1,2), (3,4)] -> (1,2,3,4)
flattened = sum(similar_items, ()) …Run Code Online (Sandbox Code Playgroud) python machine-learning pandas scikit-learn recommender-systems
我正在尝试创建一个选择字段,其中的值应该动态计算。声明是:
payment_mode = fields.Selection('_compute_selection', string="Payment mode", default="cash")
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和功能:
@api.model
def _compute_selection(self):
context = dict(self._context or {})
active_ids = context.get('active_ids')
active_model = context.get('active_model')
invoices = self.env[active_model].browse(active_ids)
type_payment = MAP_INVOICE_TYPE_PARTNER_TYPE[invoices[0].type]
if type_payment == "expense":
if active_model == "account.invoice":
payment_mode = [('cash', 'Cash'),
('idoklad', 'Internal'),
('transfer', 'Bank transfer')]
else:
payment_mode = [('cash', 'Cash'),
('transfer', 'Bank transfer')]
else:
if active_model == "account.invoice":
payment_mode = [('cash', 'Cash'),
('idoklad', 'Internal')]
else:
payment_mode = [('cash', 'Cash')]
return payment_mode
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所见声明:
<field name="payment_mode" widget="radio" />
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但是,在模块升级时我收到此错误:
File "/home/openuser/erp10/odoo/models.py", line …Run Code Online (Sandbox Code Playgroud) 如何连接Many2one字段,打开下拉列表所有车都可见.我需要[id]和[name].
例如:
[01]奥迪,
[02]宝马
car_id = fields.Many2one('my.cars', 'Cars')
@api.multi
def name_get(self):
???
Run Code Online (Sandbox Code Playgroud) 我有一个DocumentTypeDetector带有detectForRequest()方法的类。我正在做相应的测试,但是我无法验证是否抛出了定制的异常,我正在使用JUNIT 5。
我在这里进行了评论,但是答案并没有帮助我,这是我在以下示例中编写的代码:
@Test
public void tryThrowExceptionForInvalidRequest() throws Exception{
InvalidInputRequestType exceptionThrown = Assertions.assertThrows(
InvalidInputRequestType.class,
() -> {
throw new InvalidInputRequestType("La petición debe estar en un formato valido JSON o XML");
}
);
assertEquals("La petición debe estar en un formato valido JSON o XML", exceptionThrown.getMessage());
}
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但这并不能告诉我有关测试的任何信息
我需要验证我的方法是否返回了相应的异常,如下所示:
@Test
public void tryThrowExceptionForInvalidRequest() throws Exception{
String invalid = "Este es un request invalido";
assertIsThrown(InvalidInputRequestType.class, detector.detectForRequest(invalid));
}
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我该如何测试?
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