小编Ali*_*Ali的帖子

我一直在尝试用OpenGL ES创建自己的球体,我按照这里描述的数学运算http://www.math.montana.edu/frankw/ccp/multiworld/multipleIVP/spherical/learn.htm

然而,当我绘制球体(只是顶点)时,只绘制了一半球体.你能指点一下我在下面给出的代码中的确切问题:

public class Sphere {

    static private FloatBuffer sphereVertex;
    static private FloatBuffer sphereNormal;
    static float sphere_parms[]=new float[3];

    double mRaduis;
    double mStep;
    float mVertices[];
    private static double DEG = Math.PI/180;
    int mPoints;

    /**
     * The value of step will define the size of each facet as well as the number of facets
     *  
     * @param radius
     * @param step
     */

    public Sphere( float radius, double step) {
        this.mRaduis = radius;
        this.mStep = step;
        sphereVertex = FloatBuffer.allocate(40000);
        mPoints = …

看看这个例子：https : //github.com/googlesamples/android-architecture-components/tree/master/GithubBrowserSample 我已经在我的一个副项目中实现了相同的模式，但是我在测试工作时遇到了困难正如预期的那样。

我正在尝试测试我的存储库类之一。该测试检查存储库是否从 api 获取数据以及观察者的值是否发生变化。

这是测试类

@RunWith(JUnit4.class)
public class TimelineRepositoryTest {

    private SharedPreferences sharedPreferences;
    private DatabaseDao databaseDao;
    private ApiService apiService;
    private TimelineRepository timelineRepository;

    @Rule
    public InstantTaskExecutorRule instantExecutorRule = new InstantTaskExecutorRule();

    @Before
    public void setup() {
        sharedPreferences = mock(SharedPreferences.class);
        databaseDao = mock(DatabaseDao.class);
        apiService = mock(ApiService.class);
        timelineRepository = new TimelineRepository(apiService, sharedPreferences, databaseDao);
        timelineRepository.appExecutors = new InstantAppExecutors();
    }

    @Test
    public void fetchTimelineWithForceFetch() {
        TimelineResponse timelineResponse = new TimelineResponse();
        when(sharedPreferences.getLong(PreferenceUtils.PREFERENCE_LAST_TIMELINE_REFRESH, 0)).thenReturn(0L);
        when(apiService.retrieveTimeline()).thenReturn(ApiUtil.successCall(timelineResponse));

        MutableLiveData<List<Event>> dbData = new MutableLiveData<>();
        when(databaseDao.loadEvents()).thenReturn(dbData);
        Observer observer = …

我一直在打自己,因为我认为这是一个简单的问题,但不知何故,我找不到解决方案.

我根据触摸移动事件旋转CCSprite关于其锚点.这是我用来旋转精灵的代码.

CGPoint previousLocation = [touch previousLocationInView:[touch view]];
CGPoint newLocation = [touch locationInView:[touch view]];

//preform all the same basic rig on both the current touch and previous touch
CGPoint previousGlLocation = [[CCDirector sharedDirector] convertToGL:previousLocation];
CGPoint newGlLocation = [[CCDirector sharedDirector] convertToGL:newLocation];

CCSprite *handle = (CCSprite*)[_spriteManager getChildByTag:HANDLE_TAG];

CGPoint previousVector = ccpSub(previousGlLocation, handle.position);
CGFloat firstRotateAngle = -ccpToAngle(previousVector);
CGFloat previousTouch = CC_RADIANS_TO_DEGREES(firstRotateAngle);

CGPoint currentVector = ccpSub(newGlLocation, handle.position);
CGFloat rotateAngle = -ccpToAngle(currentVector);
CGFloat currentTouch = CC_RADIANS_TO_DEGREES(rotateAngle);

float rotateAmount = (currentTouch - previousTouch);
handle.rotation += rotateAmount; …