小编the*_*web的帖子

所以我使用navigator.geolocation.getCurrentPosition jammy有一个相当简单的JS.

$(document).ready(function(){
  $("#business-locate, #people-locate").click(function() {
    navigator.geolocation.getCurrentPosition(foundLocation, noLocation);
  });

  navigator.geolocation.getCurrentPosition(foundLocation, noLocation);

  function foundLocation(position) {
    var lat = position.coords.latitude;
    var lon = position.coords.longitude;
    var userLocation = lat + ', ' + lon;
    $("#business-current-location, #people-current-location").remove();
    $("#Near-Me")
      .watermark("Current Location")
      .after("<input type='hidden' name='business-current-location' id='business-current-location' value='"+userLocation+"' />");
    $("#people-Near-Me")
      .watermark("Current Location")
      .after("<input type='hidden' name='people-current-location' id='people-current-location' value='"+userLocation+"' />");
  }
  function noLocation() {
    $("#Near-Me").watermark("Could not find location");
    $("#people-Near-Me").watermark("Could not find location");
  }
})//end DocReady

基本上这里发生的是我们得到当前位置,如果得到的话,两个"水印"被放置在两个字段中,表示"当前位置",两个隐藏字段用lat-long数据作为它们的值(它们被删除)在一开始所以他们不会每次都重复).还有两个按钮,它们具有与之相关的点击功能,可以执行相同的操作.不幸的是,每三次左右,它都有效.这有什么问题???