我有一节课:
class SymbolIndexer {
protected:
SymbolIndexer ( ) { }
public:
static inline SymbolIndexer & GetUniqueInstance ( )
{
static SymbolIndexer uniqueinstance_ ;
return uniqueinstance_ ;
}
};
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我该如何修改它以禁用如下代码:
SymbolIndexer symbol_indexer_ = SymbolIndexer::GetUniqueInstance ( );
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并且只允许以下代码:
SymbolIndexer & ref_symbol_indexer_ = SymbolIndexer::GetUniqueInstance ( );
Run Code Online (Sandbox Code Playgroud) 在尝试构建一个对延迟敏感的应用程序时,需要每秒发送100条消息,每条消息都有时间字段,我们要考虑优化gettimeofday.首先想到的是rdtsc基于优化.有什么想法吗 ?还有其他指针吗?返回的时间值所需的准确度以毫秒为单位,但如果该值偶尔与接收器不同步1-2毫秒,则不是很大.试图比62纳秒的gettimeofday做得更好
在接口中定义函数时:
virtual void ModifyPreComputedCoeffs ( std::vector < IndexCoeffPair_t > & model_ ) = 0;
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我们想要指定不应该在push_back等意义上改变向量model_操作不应该对向量进行操作,但是可以更改model_中的IndexCoeffPair_t结构对象.我们该如何指定?
virtual void ModifyPreComputedCoeffs ( const std::vector < IndexCoeffPair_t > & model_ ) = 0;
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我觉得不行.
上下文是进程间通信,其中一个进程("服务器")必须将固定大小的结构发送到在同一台机器上运行的许多侦听进程("客户端").
在Socket Programming中我很自在.为了使服务器和客户端之间的通信更快并减少副本数量,我想尝试使用共享内存(shm)或mmaps.
操作系统是RHEL 64位.
由于我是新手,请建议我应该使用哪个.如果有人能指点我一本书或在线资源来学习同样的东西,我会很感激.
谢谢你的回答.我想补充一点,服务器(市场数据服务器)通常会接收多播数据,这将导致它每秒向"客户端""发送"大约200,000个结构,其中每个结构大约为100字节.shm_open/mmap的实现是否仅对大型数据块或大量小型结构的性能优于套接字?
是否有内置函数或运算符在R中执行以下操作:
ElementwiseMultiply <- function ( a_, b_ )
{
c_ = a_ ;
for ( i in 1:ncol(a_) )
{
c_[,i] = ( a_[,i] * b_ ) ;
}
return ( c_ );
}
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例如
> a_
[,1] [,2]
[1,] 1 4
[2,] 2 3
[3,] 3 2
> b_
[,1]
[1,] 2
[2,] -1
[3,] 1
> ElementwiseMultiply ( a_, b_ )
[,1] [,2]
[1,] 2 8
[2,] -2 -3
[3,] 3 2
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git空白困境
我如何设置不仅仅因为合并上的空格而报告冲突,如下所示?
<<<<<<< HEAD
open RESDBFILE, "< $this_day_result_file_";
while ( my $resdbline_ = <RESDBFILE> )
{
my @rwords_ = split ' ', $resdbline_;
if ( exists $uncaliberated_strategies_{$rwords_[0]} )
{ # if this strategy_filename_base was there in @strategy_filevec_
delete $uncaliberated_strategies_{$rwords_[0]};
}
}
close RESDBFILE;
=======
open RESDBFILE, "< $this_day_result_file_";
while ( my $resdbline_ = <RESDBFILE> )
{
my @rwords_ = split ' ', $resdbline_;
if ( exists $uncaliberated_strategies_{$rwords_[0]} )
{ # if this strategy_filename_base was there in @strategy_filevec_
delete $uncaliberated_strategies_{$rwords_[0]}; …Run Code Online (Sandbox Code Playgroud) 我一直在使用boost.build或b2来构建项目.我正在尝试添加类似的C++ 11结构auto,begin但是b2 release使用Jamfile的目录中的标准调用无法识别这些.
鉴于这是一个基本问题,我想可能有重复,但我找不到任何.我只想从boost中获取当前的iso_date(如20110503).
有什么指针吗?
当使用clang构建时,它似乎使用gcc4.4.4版本的包含文件,而我希望它使用更新的版本.
[ ~ ] locate move.h
/home/apps/gcc_versions/gcc-4_8_install/include/c++/4.8.3/bits/move.h
/usr/include/c++/4.4.4/bits/move.h
/usr/local/include/c++/4.7.1/bits/move.h
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gcc路径:
`gcc -print-prog-name=cc1plus` -v
ignoring nonexistent directory "/apps/gcc_versions/gcc-4_8_install/lib/gcc/x86_64-unknown-linux-gnu/4.8.3/../../../../x86_64-unknown-linux-gnu/include"
#include "..." search starts here:
#include <...> search starts here:
/apps/gcc_versions/gcc-4_8_install/lib/gcc/x86_64-unknown-linux-gnu/4.8.3/../../../../include/c++/4.8.3
/apps/gcc_versions/gcc-4_8_install/lib/gcc/x86_64-unknown-linux-gnu/4.8.3/../../../../include/c++/4.8.3/x86_64-unknown-linux-gnu
/apps/gcc_versions/gcc-4_8_install/lib/gcc/x86_64-unknown-linux-gnu/4.8.3/../../../../include/c++/4.8.3/backward
/apps/gcc_versions/gcc-4_8_install/lib/gcc/x86_64-unknown-linux-gnu/4.8.3/include
/usr/local/include
/apps/gcc_versions/gcc-4_8_install/include
/apps/gcc_versions/gcc-4_8_install/lib/gcc/x86_64-unknown-linux-gnu/4.8.3/include-fixed
/usr/include
End of search list.
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gcc包括工作正常但是有了clang它失败了
[ ~ ] clang -v
clang version 3.5 (http://llvm.org/git/clang.git 8e674ff884113429b53d23b18409caf67aaec1b7) (http://llvm.org/git/llvm.git 7add5421a686877e0aa87616b92b1f5a85c6feee)
Target: x86_64-unknown-linux-gnu
Thread model: posix
Found candidate GCC installation: /usr/lib/gcc/i686-redhat-linux/4.4.4
Found candidate GCC installation: /usr/lib/gcc/i686-redhat-linux/4.4.7
Found candidate GCC installation: /usr/lib/gcc/x86_64-redhat-linux/4.4.4
Found candidate GCC installation: /usr/lib/gcc/x86_64-redhat-linux/4.4.7
Selected GCC installation: …Run Code Online (Sandbox Code Playgroud) 我使用以下代码来分析我的操作,以优化我的函数中的cpu周期.
static __inline__ unsigned long GetCC(void)
{
unsigned a, d;
asm volatile("rdtsc" : "=a" (a), "=d" (d));
return ((unsigned long)a) | (((unsigned long)d) << 32);
}
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我不认为这是最好的,因为即使连续两次通话也给了我"33"的差异.有什么建议 ?