小编oko*_*nov的帖子

我重写NSURLProtocol并需要返回具有特定statusCode的HTTP响应.NSHTTPURLResponse没有statusCode setter,所以我尝试用以下方法覆盖它:

@interface MyHTTPURLResponse : NSHTTPURLResponse {} 

@implementation MyHTTPURLResponse

    - (NSInteger)statusCode {
        return 200; //stub code
    }
@end

重写的NSURLProtocol的startLoading方法如下所示:

-(void)startLoading
{   
   NSString *url = [[[self request] URL] absoluteString];
   if([url isEqualToString:SPECIFIC_URL]){
       MyURLResponse *response = [[MyURLResponse alloc] initWithURL:[NSURL URLWithString:@"http://fakeUrl"]
       MIMEType:@"text/plain"
       expectedContentLength:0  textEncodingName:nil];

       [[self client] URLProtocol:self     
            didReceiveResponse:response 
            cacheStoragePolicy:NSURLCacheStorageNotAllowed];

       [[self client] URLProtocol:self didLoadData:[@"Fake response string"
            dataUsingEncoding:NSASCIIStringEncoding]];

       [[self client] URLProtocolDidFinishLoading:self];                

       [response release];

    }
    else{   
        [NSURLConnection connectionWithRequest:[self request] delegate:self];   
    }
}

但是这种方法不起作用,在NSURLProtocol中创建的响应总是在网页上使用statusCode = 0.同时,NSURLConnection从网络返回的响应具有正常的预期statusCodes.

任何人都可以请求有关如何为创建的NSURLResponse显式设置statusCode的想法？感谢名单.