小编M.A*_*nto的帖子

现有代码片段：

if sup_usr_only:
    query_ob = query_ob.filter(
        or_(
            and_(
                Department.id.in_(login_user.department_ids),  # logic is OK - checked.
                model.visibility == VISIBLE_DEPT
            ),

            and_(
                model.visibility == VISIBLE_COMPANY,
                model.company_id == login_user.company_id
            ))
    )
else:
    query_ob = query_ob.filter(
        or_(
            and_(
                Department.id.in_(login_user.department_ids),  # logic is OK - checked.
                model.visibility == VISIBLE_DEPT
            ),
            model.visibility == VISIBLE_GLOBAL,
            and_(
                model.visibility == VISIBLE_COMPANY,
                model.company_id == login_user.company_id
            ))
    )

是否有一种方法可以通过内联 if 检查或任何其他优化来最小化代码片段？想要像下面这样（语法上错误）：

query_ob = query_ob.filter(
            or_(
                and_(
                    Department.id.in_(login_user.department_ids),
                    model.visibility == VISIBLE_DEPT
                ),
                model.visibility == VISIBLE_GLOBAL if not sup_usr_only,
                and_(
                    model.visibility == VISIBLE_COMPANY, …

在对部署在 tomcat 7 上的遗留 Java Spring Maven 项目进行调查时，日志如下所示：

2018-08-29 18:16:42:471 +0600 [http-bio-8080-exec-494] [错误]

要求揭开号码的神秘面纱

执行-

那么“exec”的基本含义是什么？对于上述情况来说是494 。