小编Dom*_*lan的帖子

AngularJs使用SubMenu创建上下文菜单

我想用angularjs在指令中创建一个上下文菜单,我可以创建一个菜单但不能用子菜单创建.我的意思是,在悬停时打开子菜单.

示例小提琴:示例上下文菜单

我的控制器:

$scope.menuOptions = [
        ['New User', function () {
           console.log("New User");
        }],
        ['Delete', function () {
           console.log("Delete");
        }]
    ]; 
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这个小提琴是非常好的,只有我想在这个上下文菜单中添加子菜单.如何根据此示例创建子菜单?

javascript model-view-controller contextmenu dynamically-generated angularjs

2
推荐指数
1
解决办法
3570
查看次数

查询Mongodb子文档错误将循环结构转换为JSON

我有一个包含子文档数组的文档:

{
  "company": "test plc",
  "address": [
    {
      "addr1": "37",
      "addr2": "",
      "addr3": "test",
      "addr4": "",
      "addrcity": "",
      "addrcounty": "test",
      "addrpostcode": "test"
    },
    {
      "addr1": "37",
      "addr2": "",
      "addr3": "test",
      "addr4": "",
      "addrcity": "",
      "addrcounty": "test",
      "addrpostcode": "test"
    },
    {
      "addr1": "37",
      "addr2": "",
      "addr3": "test",
      "addr4": "",
      "addrcity": "",
      "addrcounty": "test",
      "addrpostcode": "test"
    }
  ],
  "contacts": [
    {
      "name": "test",
      "surname": "testing",
      "title": "master"
    },
    {
      "name": "test",
      "surname": "testing",
      "title": "master"
    }
  ]
}
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我想做的是通过搜索contacts.surname属性返回文档列表。

var …
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json mongodb node.js express

1
推荐指数
3
解决办法
4645
查看次数