小编kit*_*ang的帖子

我的代码:

    #!/bin/sh
    #filename:choose.sh
    read choose
    [ "$choose" == "y" -o "$choose" == "Y" ] && echo "Yes" && exit 0
    [ "$choose" == "n" -o "$choose" == "N" ] && echo "No"  && exit 0
    echo "Wrong Input" && exit 0

但是当我执行时

    sh ./choose.sh

终端提示我

   [: 4: n: :Unexpected operator
   [: 5: n: :Unexpected operator

我的bash脚本有什么错误吗？谢谢!

在bash脚本中

if [ 1 ]
then
   echo "Yes"
else
   echo "No"
fi

输出: Yes

它表示'1'被视为真值.

但在代码中:

word = Linux
letter = nuxi
if echo "$word" | grep -q "$letter"
then
    echo "Yes"
else
    echo "No"
fi

输出:没有

但是No会返回1,为什么结果是否

关键字如何echo "$word" | grep -q "$letter"测试命令返回的值后No？