我有一个关于如何在R中NA使用as.numeric函数时避免的问题.如下所示,我有一个字符变量(但它的值是数字)cumulative_viewers,我想将它转换为数字,as.numeric但它无法正常工作.问题是当数值的位数超过四位as.numeric时,NA即使值是数字,函数也会返回.例如,as.numeric函数与'999'或'997'的值很好地工作但是当位数超过4时,例如'1000'或'1001'或'999999',则该as.numeric函数NA =.=;;;;;;;;;;;;不返回其实际数值. ...
有谁可以帮我解决问题？我发了一天来处理它但是还没有答案TT> TT
paste(data_without_duplicates$cumulative_viewers)
[1] "12,983,336" "12,323,294" "11,375,954" "10,917,221" "10,667,700"
[6] "10,292,386" "9,350,192" "9,135,520" "9,001,309" "8,653,415"
[11] "7,784,755" "7,508,976" "7,362,790" "6,959,047" "6,706,543"
.....
[1426] "1,026" "1,024" "1,023" "1,020" "1,017"
[1431] "1,016" "1,013" "1,011" "1,001" "1,000"
[1436] "1,000" "999" "997" "994" "990"
[1441] "989" "988" "984" "982" "979"
[1446] "974" "972" "971" "966" "961"
as.numeric(data_without_duplicates$cumulative_viewers)
[1] NA NA NA NA NA …只是一个简短的问题...任何人PLZ帮我如何阅读R中的以下文本文件..
如果#(分隔符)彼此相邻......这意味着缺少价值......
任何的想法？还是提示？谢谢你的好意
20040215#680# - .6#7.6#1457#-7.3#735#1.2#340.3#13.6#1427#0#0 ## - 7.3#735#7.6#1457 ## = 98829
18#680#.4#11.1 #1541#-7.3#635#.9#130.1#6.6#1137#0#0 ## - 7.3#635#11.1#1541 ## = 98834 20040221
#680 ########## 7#2 #1600#1.7#559#7.3#1604 ## = 98835 20040222
#680 ########## 1 ##### 6.8#1108 ## = 98836
20040223#680 ####### ### 0#0 #### 6.8#1602 ## = 98837
r ×2