小编vno*_*oec的帖子

我想使用angular-ui ui.select来填充a multiple dropdown field.我想将选定的对象传递给ng-model并将其映射到我的选项,包含相同结构的对象,但不是来自同一个源:

<div ng-repeat="training in trainings">
    <form class="form-horizontal" role="form">
        <ui-select multiple ng-model="training.skills" theme="select2" ng-disabled="disabled">
            <ui-select-match placeholder="Wähle Skills...">{{$item.name}}</ui-select-match>
            <ui-select-choices group-by="skillTypeGrp" repeat="skill.id as skill in skills | filter: $select.search">
                <span>{{skill.name}}</span>
            </ui-select-choices>
        </ui-select>
    </form>
</div>

带有示例培训的trainings列表ng-repeat如下所示:

[{"description": "",
  "skills": [{"type": "tech",
              "name": "C",
              "id": 194}],
  "id": 1,
  "name": "Test"}]

我的skills列表ui-select-choices包含与以下相同的数据结构training.skills:

[{"type": "tech",
  "name": "C#",
  "id": 194},
 {"type": "tech",
  "name": "Java",
  "id": 197},
 ...]

不幸的是,这不起作用.ui-select清空我training.skills,给我一个空白的选择字段.我知道angularjs无法映射这些对象,如果它们不是来自同一个数组,就像这篇博文中所述.它建议使用 …