小编Luk*_*uke的帖子

我正在尝试更新数据库中的记录而不刷新表单.我有grid.php页面与表单来显示和更新记录.然后,我有一个文件update.php与UPDATE查询.第三个文件是js1.jsAJAX代码.如果我映射grid.php到update.php通过action=update.php,更新询问的伟大工程.但是一旦我尝试包含js1.js文件以防止表单刷新,它就会停止工作.

代码如下:

grid.php

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="j1.js"></script>
<?php //query.php
    require_once 'header.php';
    if (!$loggedin) die();

    $query = "SELECT SpringMgmt.SpringMgmtID, 
                     SpringMgmt.SpringMgmtActiveYear, 
                     SpringMgmt.PoolID, 
                     SpringMgmt.Notes, 
                     SpringMgmt.SOIEstSubmitted,
                     SpringMgmt.EstAdditional, 
                     SpringMgmt.SOIMeetingScheduled, 
                     Pool.Pool, 
                     Pool.AreaManager, 
                     Employees.EmployeeID, 
                     Employees.FirstName
              FROM SpringMgmt
                   INNER JOIN Pool ON SpringMgmt.PoolID = Pool.PoolID
                   INNER JOIN Employees ON Employees.EmployeeID = Pool.AreaManager ";
    $result = mysql_query($query);
    echo "OK</div>";
    if (!$result) die ("Database access failed0: " . mysql_error());

    //TABLE AND ITS HEADING
    echo …

我在创建一个可以调用handleSearch函数的导航按钮时遇到问题.我收到一条消息Argument of '#selector' cannot refer to local function.任何帮助,将不胜感激!

override func viewDidLoad() {
   // various code

   func setupNavBarButtons() {
       let searchImage = UIImage(named:"search_icon")
       let searchBarButtonItem = UIBarButtonItem(image: searchImage, style: .plain, target: self, action: #selector(handleSearch(sender:)))
        navigationItem.rightBarButtonItems = [searchBarButtonItem]

    }

    func handleSearch(sender: UIBarButtonItem) {
        print(123)
    }
}