我的要求
我正在制作一个也有移动版的网站.所以,我正在以API为中心.现在我想在没有OAuth复杂性的情况下使我的API安全,因为我需要的安全性非常简单.我不希望有权访问api链接的任何人能够访问我的数据.
所以,我遇到了这篇文章http://www.thebuzzmedia.com/designing-a-secure-rest-api-without-oauth-authentication/这是非常惊人的,并且清除了我的大部分疑虑.
现在,我正在尝试重新创建文章中的任何内容.我正在使用Laravel 5框架进行PHP开发.
我想确保移动应用程序和Web版本仅使用API,而不是其他任何人.我见过像api这样的链接
example.com/fetchallinformation&publicKey=<something>&Hashkey?<some_hash_key>
现在,我明白这个键是通过hash_hmac()在php中使用函数生成的.
我的方法
我的困惑
我不确定这是否是正确的方法.
我们可以hash_hmac()通过解密哈希来获取用于生成哈希的数据吗？
我有两个一维数组，我需要找出它们之间的马哈拉诺比斯距离。
阵列1
-0.125510275,0.067021735,0.140631825,-0.014300184,-0.122152582,0.002372072,-0.050777748,-0.106606245,0.149123222,-0.159149423,0.210138127,0.031959131,-0.068411253,-0.038253143,-0.024590122,0.101361006,-0.160774037,-0.183688596,-0.07163775,-0.096662685,-0.000117288,0.14251323,-0.030461289,-0.006710192,-0.217195332,-0.338565469,-0.030219197,-0.100772612,0.144092739,-0.092911556,-0.008420993,0.042907588,-0.212668449,-0.009366207,-7.01E-05,0.134508118,-0.015715659,-0.050884761,0.18804647,0.04946585,-0.242626131,0.099951334,0.053660966,0.275807977,0.216019884,-0.009127878,0.019819722,-0.043750495,0.12940146,-0.259942383,0.061821692,0.107142501,0.098196507,0.022301452,0.079412982,-0.131031215,-0.049483716,0.126781181,-0.195536733,0.077051811,0.061049294,-0.039563753,0.02573989,0.025330214,0.204785526,0.099218346,-0.050533134,-0.109173119,0.205652237,-0.168003649,-0.062734045,0.100320764,-0.063513778,-0.120843001,-0.223983109,0.075016715,0.481291831,0.107607022,-0.141365036,0.075003348,-0.042418435,-0.041501854,0.096700639,0.083469011,-0.033227846,-0.050748199,-0.045331556,0.065955319,0.26927036,0.082820699,-0.014033476,0.176714703,0.042264186,-0.011814327,0.041769091,-0.00132945,-0.114337325,-0.013483777,-0.111367472,-0.051828772,-0.022199111,0.030011443,0.015529033,0.171916366,-0.172722578,0.214662731,-0.0219073,-0.067695767,0.040487193,0.04814541,0.003313571,-0.01360167,0.115932293,-0.235844463,0.185181856,0.130868644,0.010789306,0.171733275,0.059378762,0.003508842,0.039326921,0.024174646,-0.195897669,-0.088932432,0.025385177,-0.134177506,0.08158315,0.049005955
并且，数组 2
-0.120652862,0.030241199,0.146165773,-0.044423241,-0.138606027,-0.048646796,-0.00780057,-0.101798892,0.185339138,-0.210505784,0.1637595,0.015000292,-0.10359703,0.102251172,-0.043159217,0.183324724,-0.171825036,-0.173819616,-0.112194099,-0.161590934,-0.002507193,0.163269699,-0.037766434,0.041060638,-0.178659558,-0.268946916,-0.055348843,-0.11808344,0.113775767,-0.073903576,-0.039505914,0.032382272,-0.159118786,0.007761603,0.057116233,0.043675732,-0.057895001,-0.104836114,0.22844176,0.055832602,-0.245030299,0.006276659,0.140012532,0.21449241,0.159539059,-0.049584024,0.016899824,-0.074179329,0.119686954,-0.242336214,-0.001390997,0.097442642,0.059720818,0.109706804,0.073196828,-0.16272822,0.022305552,0.102650747,-0.192103565,0.104134969,0.099571452,-0.101140082,-0.038911857,0.071292967,0.202927336,0.12729995,-0.047885433,-0.165100336,0.220239595,-0.19612211,-0.075948663,0.096906625,-0.07410948,-0.108219706,-0.155030385,-0.042231761,0.484629512,0.093194947,-0.105109185,0.072906494,-0.056871444,-0.057923764,0.101847053,0.092042476,-0.061295755,-0.031595342,-0.01854251,0.074671492,0.266587347,0.052284949,0.003548023,0.171518356,0.053180017,-0.022400264,0.061757766,0.038441688,-0.139473096,-0.05759665,-0.101672307,-0.074863717,-0.02349415,-0.011674869,0.010008151,0.141401738,-0.190440938,0.216421023,-0.028323224,-0.078021556,-0.011468113,0.100600921,-0.019697987,-0.014288296,0.114862509,-0.162037179,0.171686187,0.149788797,-0.01235011,0.136169329,0.008751356,0.024811052,0.003802934,0.00500867,-0.1840965,-0.086204343,0.018549766,-0.110649876,0.068768717,0.03012047
我发现Scipy已经实现了该功能。然而，我对 IV 的值应该是多少感到困惑。我尝试执行以下操作
V = np.cov(np.array([array_1, array_2]))
IV = np.linalg.inv(V)
print(mahalanobis(array_1, array_2, IV))
但是，我收到以下错误：
文件“C:\Users\XXXXXX\AppData\Local\Continuum\anaconda3\envs\face\lib\site-packages\scipy\spatial\distance.py”，第 1043 行，在 mahalanobis 中 m = np.dot(np.dot (δ, VI), δ)
ValueError：形状 (128,) 和 (2,2) 未对齐：128 (dim 0) != 2 (dim 0)
编辑：
array_1 = [-0.10577646642923355, 0.09617947787046432, 0.029290344566106796, 0.02092641592025757, -0.021434104070067406, -0.13410840928554535, 0.028282659128308296, -0.12082239985466003, 0.21936850249767303, -0.06512433290481567, 0.16812698543071747, -0.03302834928035736, -0.18088334798812866, -0.04598559811711311, -0.014739632606506348, 0.06391328573226929, -0.15650317072868347, -0.13678401708602905, 0.01166679710149765, -0.13967938721179962, 0.14632365107536316, 0.025218486785888672, 0.046839646995067596, 0.09690812975168228, -0.13414686918258667, -0.2883925437927246, -0.1435326784849167, -0.17896348237991333, 0.10746842622756958, -0.09142691642045975, 0.04860316216945648, 0.031577128916978836, -0.17280976474285126, …我有以下 docker 文件，我正在使用该命令docker build -t demo:v1 .来构建映像。
FROM ubuntu:18.04
WORKDIR /app
RUN apt update \
&& apt -y upgrade \
&& apt install -y python3 \
&& apt install -y python3-pip \
&& apt install -y poppler-utils \
&& apt install -y libsm6 libxext6 libxrender-dev
RUN apt install -y postgresql
COPY requirements.txt /app/requirements.txt
RUN pip3 install -r requirements.txt
COPY . /app
CMD gunicorn -t 300 --workers 5 --bind 0.0.0.0:8080 wsgi
当我使用它构建图像时，在安装 postgresql 时，它需要输入并像这样停止构建过程
.
.
.
.
Setting …以下是我的问题的简化版本。我想创建一个(N, 1)形状 numpy 数组，它将字符串作为它们的值。但是，当我尝试插入字符串时，只会插入字符串的第一个字符。
我在这里做错了什么？
>>> import numpy as np
>>> N = 23000
>>> Y = np.empty((N, 1), dtype=str)
>>> Y.shape
(23000, 1)
>>> for i in range(N):
... Y[i] = "random string"
...
>>> Y[10]
array(['r'], dtype='<U1')
我正在使用nodejs 和Mongodb。我想使用 npm节点计划运行每个用户定义的小时数的作业，但它不起作用。
这是我的代码
var schedule = require('node-schedule');
var mailTimer = 1;
var intMail = schedule.scheduleJob('* * '+mailTimer+' * *', function(){
console.log('its run');
});
//its means its run every 1 hour.
不确定标题应该是什么，请随意编辑。我是Selenium的新手，只是在玩弄它。我尝试在我最喜欢的网站之一（10fastfingers.com）上进行实验，我经常用它来练习打字。我尝试使用最新版本的 Selenium 和 Python(3.5.*) 来自动输入。自动化可以工作，但速度真的很慢。
这是我的示例脚本，我不知道为什么它变慢。如果有人能在这里帮助我那就太好了。我原以为脚本会超过 100 WPM，但实际上只达到了37 WPM
问题是，只有两行单词可见，因此，它不会一次获取所有单词，当您继续输入单词时，单词会不断出现。所以，我不能一次接受所有单词，并将其存储在一个列表中，然后稍后循环它们。
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("http://10fastfingers.com/typing-test/english")
input = driver.find_element_by_id("inputfield")
for i in range(300):
word = driver.find_element_by_class_name("highlight")
word = word.text
print("Typing word ", word)
input.send_keys(word)
input.send_keys(Keys.SPACE)
更新
我尝试获取之前的所有单词，而不是按照 @ alecxecfind_element_*的建议在循环内使用。为此，我必须使用BeautifulSoup来解析 HTML，因为它是字符串格式，并且我无法使用它的任何函数。以下脚本将打字速度提高到138 WPM。但是，我注意到前 20 秒的打字速度非常快，然后速度开始逐渐下降。请随时在您的计算机上试用该脚本，并让我知道该脚本在您的系统上实现的测试（WPM）结果。也许这也取决于系统配置。我不知道。这是内存问题吗？或者代码问题？知道如何解决这个问题吗？find_element_*
修改代码
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from bs4 import BeautifulSoup
driver = webdriver.Firefox()
driver.get("http://10fastfingers.com/typing-test/english")
input = …我正在尝试从另一个 Django 应用程序中的一个 Django 应用程序导入一个类。
mainProjectFolder
|--__init__.py
|--manage.py
|--app1
|--__init__.py
|--class1.py
|--app2
|--__init__.py
|--anotherClass.py
|--mainProjectFolder
|--__init__.py
|--settings.py
...
在app2.anotherClass.py，我在做：
from mainProjectFolder.app1.class1 import Class1
我收到以下错误：
ImportError: No module named 'mainProjectFolder.app1'
我在我注册的应用程序INSTALLED_APPS中settings.py的文件也是如此。
如果有任何不清楚的地方，请告诉我，我将编辑所需的内容。
我正在使用 Docker 来设置我的 Python 环境。因为，我正在使用python:3.6-slim基本图像。
我现在需要向一个仅在内部网中可用的 URL 发送一个 get 请求（假设它是https://internal.company.com/API/some_value）。我在 AWS EC2 上使用 Ubuntu 服务器，我试图在其中构建此映像。
从那个 EC2 服务器，我能够请求上述 URL，但是，当我从 docker 容器内部执行相同操作时，我收到以下错误。
Traceback (most recent call last):
File "/usr/local/lib/python3.6/site-packages/urllib3/connectionpool.py", line 672, in urlopen
chunked=chunked,
File "/usr/local/lib/python3.6/site-packages/urllib3/connectionpool.py", line 376, in _make_request
self._validate_conn(conn)
File "/usr/local/lib/python3.6/site-packages/urllib3/connectionpool.py", line 994, in _validate_conn
conn.connect()
File "/usr/local/lib/python3.6/site-packages/urllib3/connection.py", line 394, in connect
ssl_context=context,
File "/usr/local/lib/python3.6/site-packages/urllib3/util/ssl_.py", line 370, in ssl_wrap_socket
return context.wrap_socket(sock, server_hostname=server_hostname)
File "/usr/local/lib/python3.6/ssl.py", line 407, in wrap_socket
_context=self, _session=session)
File "/usr/local/lib/python3.6/ssl.py", line 817, in …采用以下简化示例.
class A(object):
variable_A = 1
variable_B = 2
def functionA(self, param):
print(param+self.variable_A)
print(A.functionA(3))
在上面的示例中,我收到以下错误
Traceback (most recent call last):
File "python", line 8, in <module>
TypeError: functionA() missing 1 required positional argument: 'param'
但是,如果我删除self,在函数声明中,我无法访问变量variable_A和variable_B类,我得到以下错误
Traceback (most recent call last):
File "python", line 8, in <module>
File "python", line 6, in functionA
NameError: name 'self' is not defined
那么,我如何访问类变量而不是在这里得到param错误？我正在使用Python 3 FYI.
我使用 Python3.5 和 Django 作为 web api。当我提到输入时，我指的是一个 HTTP 请求参数。我有一个参数，我需要一个 JSON 数据，我需要在进一步处理之前对其进行验证。
我有一个基本的 json 结构，输入必须在其中。例如，
{
"error": "bool",
"data": [
{
"name": "string",
"age": "number"
},
{
"name": "string",
"age": "number"
},
...
]
}
以上JSON表示我希望输入的结构。键是预定义的，值表示我期望的键的数据类型。我遇到了一个执行此验证的 Python 库（jsonschema），但我找不到任何可以处理动态数据的文档。即 JSON 数组 'data' 中的对象可以是任意数量，当然这是我想出的最简单的场景来解释基本要求。在这种情况下，我如何验证我的json?
这里的解决方案没有帮助，因为它只是根据 Django 模型检查 json 是否正确。我的 json 与 Django 模型没有关系。它是一个简单的json结构。它仍然没有告诉我如何验证动态对象
python ×7
django ×2
docker ×2
numpy ×2
api ×1
automation ×1
dockerfile ×1
function ×1
hash ×1
importerror ×1
javascript ×1
json ×1
node.js ×1
php ×1
postgresql ×1
python-3.x ×1
scipy ×1
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selenium ×1
self ×1
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