order by在第二个查询中不起作用.我需要先通过DNAID然后DNBID订购
首先查询其命令为:111221
第二次查询其命令为:112112
有关我想要完成什么的更多信息和详细信息 /sf/ask/355801631/
mysql> select * from metarun;
+----+------------+-------+-------+--------------+----------+
| ID | RunGroupID | DNAID | DNBID | CONFIGTYPEID | DateTime |
+----+------------+-------+-------+--------------+----------+
| 1 | 1 | 1 | 1 | 2 | NULL |
| 2 | 1 | 1 | 2 | 2 | NULL |
| 3 | 1 | 2 | 1 | 2 | NULL |
| 4 | 2 | 1 | 1 | 4 | NULL |
| 5 …我试图将我的问题简化为我在下面写下的一个基本示例，实际问题要复杂得多，因此下面的查询可能没有多大意义，但基本概念是相同的（一个查询的数据作为另一个查询的参数）。
查询 1：
SELECT Ping.ID as PingID, Base.ID as BaseID FROM
(SELECT l.ID, mg.DateTime from list l
JOIN mygroup mg ON mg.ID = l.MyGroup
WHERE l.Type = "ping"
ORDER BY l.ID DESC
) Ping
INNER JOIN
(SELECT l.ID, mg.DateTime from list l
JOIN mygroup mg ON mg.ID = l.MyGroup
WHERE l.Type = "Base"
ORDER BY l.ID DESC
) Base
ON Base.DateTime < Ping.DateTime
GROUP BY Ping.ID
ORDER BY Ping.ID DESC;
+--------+--------+
| PingID | BaseID |
+--------+--------+
| 11 | …例如，如何获取当前工作目录并获取没有驱动器号的路径：
C:\testing\test\test
I would like to get in a variable
testing\test\test
如何修剪驱动器号？我可以使用获得完整路径
set fullPath = %CD%
我不能使用 %~d0 表示法，因为它为我提供了脚本的路径与我所在的实际工作目录
编辑：
我如何将@myarr推入$ menu（见下文）
my @myarr = (
[ "itemone", "itemoneb", "itemonec" ],
[ "itemtwo", "itemtwob", "itemtwoc" ],
[ "itemthree", "itemthewwb", "itemthreec" ],
[ "itemfour", "itemfourb", "itemfourc" ]
);
$menu = [
"List",
["itemone", \&ds2],
["itemtwo", \&ds2],
["itemthree", \&ds2],
["itemfour", \&ds2],
[ "Do Something (second)", \&ds2 ]
];
如何使用gitpython创建存档,我尝试了以下创建文件,但我无法打开它告诉我读取存档时出错,存档似乎无效或损坏
from git import *
repo = Repo(repo_path)
assert repo.bare == False
repo.archive(open("repo.tar",'w'))
我想创建一个zip文件,然后我尝试了这个但是在这里它创建了一个空的zip文件(repo的路径是正确的,因为当我使用repo.clone时它会克隆一切)
repo.archive(open("repo.zip",'w'), format="zip")
在尝试使用imagemin时,我收到了一个奇怪的警告,没有任何反应.
grunt imagemin:primary
Warning: Cannot call method 'replace' of undefined Used --force, continuing.
Done, but with warnings.
我给错误的任务如下
grunt.config 'imagemin'
primary:
options:
optimizationLevel: 7
expand: true
cwd: "assets"
src: "{img,img_two}/**/*.{jpg,jpeg,gif,png}"
dest: "public/compiled/img"
grunt.loadNpmTasks 'grunt-contrib-imagemin'
这些都行不通
src: "img/**/*.{jpg,jpeg,gif,png}"
src: "{img,img_two}/**/*.{jpg,jpeg,gif,png}"
这些工作
src: "img/**/*.jpg"src: "{img,img_two}/**/*.jpg"
所以它似乎不喜欢多个扩展语法,但为什么,它甚至是如何在示例中完成的？
更新:似乎只是PNG不起作用,无论我是自己进行扩展还是在组匹配中.我在Windows 8,NPM 1.4.3上
https://github.com/gruntjs/grunt-contrib-imagemin/issues/219
我正在集成一个ember-cliapp,里面my main site可以访问urlhttp://host/faq/....ember...routes
所以我加入baseUrl: /faq/了我的余烬
配置/ environment.js
module.exports = function(environment) {
var ENV = {
modulePrefix: 'faq',
environment: environment,
baseURL: '/faq/',
locationType: 'hash',
问题:在我的ember-cli环境中开发ember server我的资产,如(SVG,FONTS和IMAGES),现在给我一个NOT FOUND.
例如:http://host/assets/images/bg.png给我一个现在没有找到的预期http://host/faq/assets/images/bg.png.为什么会这样？
我有一个xml我怎么能得到一个节点,levelone其中有一个名为myattvalue 的属性a,然后访问它myval.我尝试引用其他帖子以使其工作,但它似乎不起作用我的xpath有什么问题
$this->myXmlObj->xpath("//levelone[myfield[attributes/myatt='a]]]"));
<myxml>
<levelone>
<myfield myatt="a" myval="aa" />
<myfield myatt="b" myval="bb" />
</levelone>
<leveltwo>
<myfield myatt="c" myval="dd" />
<myfield myatt="c" myval="dd" />
</leveltwo>
</myxml>
array
0 =>
object(SimpleXMLElement)[41]
public '@attributes' =>
array
'myval' => string 'a' (length=40)
$myVar = $this->myXmlObj->xpath("//levelone/myfield[@myatt='a']");
$myOutput = ((string)$myVar[0]->attributes()->myVal;
如何在microsoft visual studio 2010中从我的excel加载项vsto中访问特定单元格B1.
Globals.Sheet1.Range(“B3”).Value 这不起作用,因为它似乎是excel文档的语法而不是excel加载项.
编辑这似乎工作
Microsoft.Office.Interop.Excel.Worksheet activeSheet = Globals.ThisAddIn.Application.ActiveSheet as Microsoft.Office.Interop.Excel.Worksheet;
var currentCells = activeSheet.get_Range("A1", "E1");
currentCells.Select();
但那我该如何选择具体的值currentCells呢？
我不明白为什么这个GROUP_CONCAT不起作用,就外部查询而言,返回了3行所以我想通过它来组合group_concat但它不喜欢它...
http://sqlfiddle.com/#!2/24764/3
CREATE TABLE nested_category (
category_id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(20) NOT NULL,
lft INT NOT NULL,
rgt INT NOT NULL
);
INSERT INTO nested_category VALUES(1,'ELECTRONICS',1,20),(2,'TELEVISIONS',2,9),(3,'TUBE',3,4),
(4,'LCD',5,6),(5,'PLASMA',7,8),(6,'PORTABLE ELECTRONICS',10,19),(7,'MP3 PLAYERS',11,14),(8,'FLASH',12,13),
(9,'CD PLAYERS',15,16),(10,'2 WAY RADIOS',17,18);
SELECT GROUP_CONCAT(rs.category_id, ',')
FROM
(
SELECT node.category_id, node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM nested_category AS node,
nested_category AS parent,
nested_category AS sub_parent,
(
SELECT node.category_id, node.name, (COUNT(parent.name) - 1) AS depth
FROM nested_category AS node,
nested_category AS parent
WHERE node.lft BETWEEN parent.lft …