小编jot*_*tik的帖子

该finfo函数正在返回疯狂的mime类型.看下面的代码,发生了什么？

<?php
    $files = array ("css.css", "index.html", "js.js", "png.png");

    $info = finfo_open (FILEINFO_MIME_TYPE);

    for ($i = 0; $i < count ($files); $i ++) {
        $type = finfo_file ($info, $files[$i]);

        $files[$i] = $type;
    }

    finfo_close ($info);

    echo $files[0]; // text/x-c -> WHAT ?!
    echo $files[1]; // text/html -> Ok !
    echo $files[2]; // text/x-c++ -> WHAT ?!
    echo $files[3]; // image/png -> Ok !
?>

谢谢

我写了这段无辜的代码,导致了这样一个邪恶的错误:

static char * prefixed( char * pref, char *str ) {
    size_t newalloc_size = sizeof(char) * (strlen(pref) + strlen(str));
    char * result = (char*) malloc( newalloc_size );
    [...]

debug(cgdb)的输出:

Breakpoint 1, prefixed (pref=0x401345 "Env: ", str=0x4012b5 "Home") at ./src/backend/os/env.c:77
(gdb) s
(gdb) p newalloc_size 
$1 = 9
(gdb) s
envtest: malloc.c:2368: sysmalloc: Assertion `(old_top == (((mbinptr) (((char *) &((av)->bins[((1) - 1) * 2])) - __builtin_offsetof (struct malloc_chunk, fd)))) && old_size == 0) || ((unsigned long) (old_size) >=
(unsigned long)((((__builtin_offsetof …

我看过cppreference.com,他们似乎没有noexcept说明std::function(std::function&&).这对我来说似乎很奇怪.在这种情况下,标准是否真的没有给出保证？

我似乎无法下载Android Studio.我去了AS的官方下载页面,但没有任何反应.我没有弹出窗口或什么也没有,我的互联网连接很好.请帮忙.

我需要有关使用Dapper和Oracle映射枚举的帮助.

我在Oracle类型NUMBER(1)中有一个字段,必须在我的实体中变成一个枚举.

public Status Status { get; set; }

状态是枚举:

public enum Status
{
    [Description("Inactive", "0")]
    Inactive = 0,

    [Description("Active", "1")]
    Active = 1,
 }

如何使用Dapper进行映射？

有没有一种方便的格式化std::chrono::duration为指定格式的方法？

std::chrono::high_resolution_clock::time_point now, then;
then = std::chrono::high_resolution_clock::now();
// ...
now = std::chrono::high_resolution_clock::now();
auto duration = now - then;

// base in microseconds:
auto timeInMicroSec =
      std::chrono::duration_cast<std::chrono::microseconds>(duration);

如何设置格式timeInMicroSec一样ss::ms::us？

鉴于此C++ 11代码:

#include <type_traits>

enum Enum { EnumValue };

template <typename>
struct Pred { constexpr static bool const value = true; };

template <
        typename T,
        typename ::std::enable_if<
            Pred<T>::value,
            Enum
        >::type = EnumValue>
class Huh {};

template <typename T>
constexpr bool f(Huh<T> const &) noexcept { return true; }

static_assert(f(Huh<int>()), "");

我从GCC 7.3.0收到以下错误消息:

test.cpp:19:27: error: no matching function for call to 'f(Huh<int>)'
 static_assert(f(Huh<int>()), "");
                           ^
test.cpp:17:16: note: candidate: template<class T> constexpr bool f(const Huh<T>&)
 constexpr bool f(Huh<T> const &) noexcept …

I need a way to compare values of type __m128i in C++ for a total order between any values of type __m128i. The type of order doesn't matter as long as it establishes a total order between all values of type __m128i. Hence the comparison might be less-than between 128-bit integers or something else entirely as long as is provides a total order.

I tried using the < operator, but that didn't return a bool, but instead …

<?php
$a = file_get_contents('http://www.google.com');
echo $

为什么浏览器会返回此错误？

Warning: file_get_contents(http://www.google.com) [function.file-get-contents]: failed to open stream: Connection timed out in /home/test.php on line 2

为什么Arc-Consistency Algorithm O(cd ³)的复杂性？