小编Ely*_*man的帖子

我刚学会了如何使用静态方法.我试图用这段代码计算每个星球的引力:

/**
 * Calculates the acceleration due to gravity on each planet, and then displays the     info in a nice table and in a text file
 * 
 * @author Ely Eastman
 * @version 14.8.2014
 */
public class GravityV1
{
//method for calulating gravity
public static double [] gravCalc(double [] d, double [] m){
    double[] gravFinal = new double [d.length];
    for(int i = 0; i < d.length; i++){
       gravFinal[i] = ((6.67 * 10E-11) * m[i]) / Math.pow(((d[i] * 1000) / 2) …

我正在开发一个程序,以递归方式生成音阶中的音调频率.每个频率是比前一个频率高两个的第十二个根.该程序必须使用递归(呃,教育).当我使用这种方法时,我只是一遍又一遍地重复初始音调.这是为什么？

public static void scale(double x, double z){
double y;
  if(z == x){
     y = z * Math.pow(2, (1/12));
     System.out.println(y);
     scale (y, y); 
   }
   else if(z >= (2 * x) - 1 || z <= (2 * x) + 1){
     y = z;
     System.out.println();
   }
   else{
     y = z * Math.pow(2, (1/12));
     scale (y, y);
   }
  System.out.println(y);
}

我正在编写夏季课程的代码,所以我不必在学校学习入门技术课程.

public class Family {
   public static void main(String[] args) throws IOException {
      String token = "";
      int counter = 0, boyBoy = 0, boyGirl = 0, girlGirl = 0;
      double ratioBB = 0.0, ratioBG = 0.0, ratioGG = 0.0;

      Scanner inFile = new Scanner(new File("MaleFemale.txt"));
      DecimalFormat df = new DecimalFormat("#.##");

      while (inFile.hasNextLine()) {
         counter++;
         token = inFile.nextLine( );
              if(token.equals("BB")) boyBoy++;
         else if(token.equals("BG") || token.equals("GB")) boyGirl++;
         else girlGirl++;
      }

      ratioBB = (boyBoy / counter) * 100;
      ratioBG = (boyGirl / …