我正在做一个使用react,redux和express的项目,我不明白react-router和express routes.js有什么区别,我需要将两者结合起来还是只使用一个?
https://github.com/reactjs/react-router
谢谢您的帮助 :)
我正在使用React js 0.14.3,我正在尝试使用react创建一个Side Menu组件但我不知道为什么我有一个"无法读取属性'refs'为null"当我使用refs之类的反应文件:https: //facebook.github.io/react/docs/more-about-refs.html 你能帮我吗?
'use strict';
import React from 'react';
import BaseComponent from './../../BaseComponent.react';
import Menu from './SidePanelMenu';
import MenuItem from './SidePanelMenuItem';
class SidePanel extends BaseComponent {
showLeft() {
this.refs.leftmenu.show();
}
render() {
return(
<div>
<button onClick={this.showLeft}>Show Left Menu!</button>
<Menu ref="leftmenu" alignment="left">
<MenuItem hash="first-page">First Page</MenuItem>
<MenuItem hash="second-page">Second Page</MenuItem>
<MenuItem hash="third-page">Third Page</MenuItem>
</Menu>
</div>
);
}
}
export default SidePanel;
Run Code Online (Sandbox Code Playgroud) 我正在做一个 Flutter 应用程序,我想从第 4 页返回到第 1 页。我有一个非常奇怪的错误:
坏状态:未来已经完成
我创建了一个简单的项目来重现这个错误:
import 'package:flutter/material.dart';
void main() => runApp(MyApp());
class MyApp extends StatelessWidget {
// This widget is the root of your application.
@override
Widget build(BuildContext context) {
return MaterialApp(
title: 'Flutter Demo',
onGenerateRoute: routes,
);
}
}
Route routes(RouteSettings settings) {
if (settings.name == '/page1') {
return MaterialPageRoute(
builder: (context) {
return Page1();
},
);
} else if (settings.name == '/page2') {
return MaterialPageRoute(
builder: (context) {
return Page2();
},
);
} else …
Run Code Online (Sandbox Code Playgroud) 我正在使用此站点的react-bootstrap:http://react-bootstrap.github.io/components.html
我想知道如何自定义这样的选项卡(在选项卡部分):
const tabsInstance = (
<Tabs defaultActiveKey={2}>
<Tab eventKey={1} title="Tab 1">Tab 1 content</Tab>
<Tab eventKey={2} title="Tab 2">Tab 2 content</Tab>
<Tab eventKey={3} title="Tab 3" disabled>Tab 3 content</Tab>
</Tabs>
);
ReactDOM.render(tabsInstance, mountNode);
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我想添加一个十字按钮来关闭它,但我没有找到如何做到这一点。你能帮我吗 ?
我想使用材料ui库中的表做出反应:http: //www.material-ui.com/#/components/table
我显示它,它工作得很好,我试图获取与我选择的行相关联的对象,但我找不到这样做的方法,我看到了属性children
或onRowSelection
但我无法得到我的对象在这里是你的代码.如何获取所选行的整个对象?
import React, { PropTypes, Component } from 'react'
import Table from 'material-ui/lib/table/table';
import TableHeaderColumn from 'material-ui/lib/table/table-header-column';
import TableRow from 'material-ui/lib/table/table-row';
import TableHeader from 'material-ui/lib/table/table-header';
import TableRowColumn from 'material-ui/lib/table/table-row-column';
import TableBody from 'material-ui/lib/table/table-body';
export default class MagicTableReact extends Component {
constructor(props) {
super(props);
this.state = {
data : [{id:0,name:"joe"},{id:1,name:"john"},{id:2,name:"Brad"},{id:3,name:"Jack"},{id:4,name:"Andrew"}],
fixedHeader: true,
fixedFooter: true,
stripedRows: false,
showRowHover: true,
selectable: true,
multiSelectable: false,
enableSelectAll: false,
deselectOnClickaway: true,
height: '300px',
};
};
_onRowSelection(e){
console.log(e)
} …
Run Code Online (Sandbox Code Playgroud) 我想按 Xamarin Form 应用程序的名称过滤对象ObservableCollection
。Person
目标是对其进行过滤ObservableCollection
以仅显示其中的一部分。
这是我的 Person 对象类:
public class Person
{
public string Name { get; set; }
public string Address { get; set; }
public string Phone { get; set; }
}
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我尝试制作这样的过滤器:
private ObservableCollection<Person> personItems = new ObservableCollection<Person>();
public ObservableCollection<Person> PersonItems
{
get { return personItems; }
set { personItems = value; OnPropertyChanged(); }
}
public void FilterPerson(string filter)
{
if (string.IsNullOrWhiteSpace(filter))
{
PersonItems = personItems;
}
else
{
PersonItems = personItems.Where((person) …
Run Code Online (Sandbox Code Playgroud) 我使用UITableView显示多个自定义单元格,而且我有一个带有UiSlider的问题,问题是要移动滑块我需要长按触摸才能移动它,否则它不会移动.我尝试在UITableView中使用多个滑块做一个简单的项目,它运行得很好.所以我想我需要在触摸时配置一些东西,但我不知道是什么.这是我的代码:
我在我的视图中有这个代码加载手势:
override func viewDidLoad() {
super.viewDidLoad()
let tap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(FormViewController.dismissKeyboard))
view.addGestureRecognizer(tap)
// without this line bellow you can't select any cell to display multiple or single choice questions
tap.cancelsTouchesInView = false
if self.navigationController!.respondsToSelector(Selector("interactivePopGestureRecognizer")) {
self.navigationController!.view.removeGestureRecognizer(navigationController!.interactivePopGestureRecognizer!)
}
notificationCenter.addObserver(self, selector: #selector(adjustForKeyboard), name: UIKeyboardWillHideNotification, object: nil)
notificationCenter.addObserver(self, selector: #selector(adjustForKeyboard), name: UIKeyboardWillChangeFrameNotification, object: nil)
}
func dismissKeyboard() {
view.endEditing(true)
}
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对于UITableView cellForRowAtIndexPath
方法:
let cell = tableView.dequeueReusableCellWithIdentifier(CurrentFormTableView.CellIdentifiers.SliderCell, forIndexPath: indexPath) as! SliderCell
cell.delegate = self
cell.slider.tag = indexPath.row
cell.display(block)
cell.selectionStyle …
Run Code Online (Sandbox Code Playgroud) 我使用TFS 2015,我看到我的构建代理处于离线状态:
我启动VsoWorker.exe来查看日志并理解错误,这是我得到的但是我从互联网上找不到任何东西:请问有什么想法吗?
16:07:57.649004 Sending trace output to log files: C:\Users\Administrator\Downloads\agent\_diag
16:07:57.649004 vsoWorker.exe was run with the following command line:
"C:\Users\Administrator\Downloads\agent\Agent\Worker\VsoWorker.exe"
16:07:57.649004 VsoWorker.Main(): Create AgentLogger
16:07:57.649980 VsoWorker.Main(): Parse command line
16:07:57.655848 ---------------------------------------------------------------------------
16:07:57.657635 System.Exception: The /name command line option is required and must have a value.
16:07:57.657635 at VsoWorker.CommandLine.ValidateCommandLine()
16:07:57.657635 at VsoWorker.CommandLine..ctor(String[] args)
16:07:57.657635 at VsoWorker.Program.Main(String[] args)
16:07:57.657635 at VsoWorker.CommandLine.ValidateCommandLine()
16:07:57.657635 at VsoWorker.CommandLine..ctor(String[] args)
16:07:57.657635 at VsoWorker.Program.Main(String[] args)
16:07:57.657635 ---------------------------------------------------------------------------
16:07:57.658878 BaseLogger.Dispose()
Run Code Online (Sandbox Code Playgroud) 我不想在reducer中sections: []
为我的对象添加属性,我从我的服务器formOpen
接收formOpen
带有其他属性的对象,我想添加这个,我该怎么做呢?谢谢
import { combineReducers } from 'redux'
import * as types from '../constants/ActionTypes'
const initialState = {
isFetching: false,
formOpen: {
}
};
export function formEditor (state = initialState, action) {
switch (action.type) {
case types.RECEIVE_OPEN_FORM:
return {
...state,
isFetching: false,
formOpen: action.formOpen
};
default:
return state;
}
}
export default combineReducers({
formEditor
})
Run Code Online (Sandbox Code Playgroud) 我正在做一个 UWP 项目,我正在使用 CommandBar。在我的命令栏中,我有多个AppBarToggleButton
,当我单击其中一个时,我不想AppBarToggleButton
取消选择另一个。有没有办法做到这一点?
这是一个简单的代码:
<CommandBar>
<AppBarToggleButton Icon="Shuffle" Label="Shuffle" Click="AppBarButton_Click" />
<AppBarToggleButton Icon="RepeatAll" Label="Repeat" Click="AppBarButton_Click"/>
<CommandBar.Content>
<TextBlock Text="Now playing..." Margin="12,14"/>
</CommandBar.Content>
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reactjs ×4
c# ×2
azure-devops ×1
build-agent ×1
express ×1
flutter ×1
material-ui ×1
offline ×1
react-router ×1
reducers ×1
redux ×1
swift2 ×1
tfs ×1
tfsbuild ×1
uitableview ×1
uwp ×1
xamarin ×1
xaml ×1