我正在尝试使用Jersey开发restful API.我有一个特定的get操作的GET API,我的GET从同一个客户端同时进行.是否可以缓存响应？任何指针都表示赞赏.
谢谢
我有 ~/.aws/credentials 和配置文件，我的代码如下
clientConfiguration.setProxyHost("MYPROXY");
clientConfiguration.setProxyPort(port);
clientConfiguration.setProxyUsername("username");
clientConfiguration.setProxyPassword("pw");
clientConfiguration.setPreemptiveBasicProxyAuth(false);
AmazonDynamoDBClient client = new AmazonDynamoDBClient(new ProfileCredentialsProvider("MY_PROFILE"),clientConfiguration);
//client.withRegion(Regions.US_EAST_1);
DynamoDBMapper mapper = new DynamoDBMapper(client);
// Get a book - Id=101
GetBook(mapper, 101);
我每次都遇到异常。我可以在 ~/.aws/credentials 的凭证文件中看到会话令牌
Error running the DynamoDBMapperQueryScanExample: com.amazonaws.services.dynamodbv2.model.AmazonDynamoDBException: The security token included in the request is invalid. (Service: AmazonDynamoDBv2; Status Code: 400; Error Code: UnrecognizedClientException; Request ID: S0NTUAHKE57VC68FM3CVBOFAKFVV4KQNSO5AEMVJF66Q9ASUAAJG)
com.amazonaws.services.dynamodbv2.model.AmazonDynamoDBException: The security token included in the request is invalid. (Service: AmazonDynamoDBv2; Status Code: 400; Error Code: UnrecognizedClientException; Request ID: S0NTUAHKE57VC68FM3CVBOFAKFVV4KQNSO5AEMVJF66Q9ASUAAJG)
AWS 开发工具包 1.11.24 …
我有以下格式的JSON,我正在尝试写入CSV:
{
"results": [{
"geo_position": {
"Field1": 11,
"Filed2": 12
},
"Field3": 13,
"Filed4": 14,
"Field5": 15
},
{
"geo_position": {
"Field1": 21,
"Filed2": 22
},
"Field3": 23,
"Filed4": 24,
"Filed5": 25
}
]
}
我期待输出像:
field1,field2,field3,field4,field5
11,12,13,14,15
21,22,23,24,25
我得到输出CSV如下:
geo_position,field3,field4,field5
{Field1:11,Field2:12}, 13,14,15
{Field2:21,Field2:22},23,24,25
我的java代码:
JSONObject jsonObj = new JSONObject(jsonArray);
System.out.println(jsonObj);
JSONArray docs = jsonObj.getJSONArray("results");
File file=new File("C:/fromJSON2.csv");
String csv = CDL.toString(docs);
FileUtils.writeStringToFile(file, csv);
有人可以帮我弄清楚为什么我会采用不同的格式.我应该怎么做以达到我期望的格式？
我有 Zookeeper 连接为 ip1:port1,ip2:port2,ip3:port3 我想在我的用户数据中使用它我该怎么做？
"ZooKeeperConnect": {
"Type": "String",
"Description": "list of IP or CNAME's for the associated zookeeper ensemble",
"AllowedPattern": "([1-9][0-9]?|[1-2][0-9]{2})(\\.([1-9][0-9]?|[1-2][0-9]{2})){3}(:[1-9][0-9]{1,4})?(,([1-9][0-9]?|[1-2][0-9]{2})(\\.([1-9][0-9]?|[1-2][0-9]{2})){3}(:[1-9][0-9]{1,4})?)*"
}
"UserData": {
"Fn::Base64": {
"Fn::Join": [
"",
[
"#!/bin/bash \n",
"echo Cache proxy vars... \n",
我想在我的用户数据中使用 ZooKeeperConnect 值
给定数字N，找到最小的偶数E，使得E> N且N和E中的数字相同。
Print NONE otherwise.
Sample:
Case1
Input
N = 34722641
Output
E = 34724126
Case2
Input
N = 8234961
Output
E = 8236194 (instead of 8236149)
我的第二种情况通过了第一种情况，我的输出错误
public static int nextDigit(int number) {
String num = String.valueOf(number);
int stop = 0;
char[] orig_chars = null;
char[] part1 = null;
char[] part2 = null;
orig_chars = num.toCharArray();
for (int i = orig_chars.length - 1; i > 0; i--) {
String previous = orig_chars[i - 1] + "";
String next = …我想通过客户端Javascript将json数据转换为pdf文件.你能指点我一个有用的方向吗？
例如,我想转换这个json
{"employees":[
{"firstName":"John", "lastName":"Doe"},
{"firstName":"Anna", "lastName":"Smith"},
{"firstName":"Peter", "lastName":"Jones"}
]}
进入pdf ...
Employees
FirstName: John LastName :Doe
FirstName: Anna LastName :Smith
FirstName: Peter LastName :Jones
我是Perl的新手.我有类似的字符串
my $http_origin_servers_list = "abc:2220,cde:40111,efg:45643";
我有一个叫做喜欢的子
executeCommand($host);
我想转换$http_origin_servers_list成数组
my @values = ("abc:2220", "cde:40111", "efg:45643");
并executeCommand依次调用每个值
executeCommand("abc:2220");
我遇到了类似这样的问题
我有一个列表,其中包含数百万字的字典,我输入一个像OSPT onlt这样的单词可以形成STOP和POST ..我想找出所有在dictonary匹配的字谜单词以优化的方式.
我解决了什么.
我给出了下面的解决方案.我会接受这个词并置换它并检查字典中存在的单词与否.但这是n*n未优化.有什么方法可以解决这个问题
我在下面遇到了一个问题但我没有得到解决方案,因此寻求你的帮助.函数GF定义如下
GF(A,B,0)=A
GF(A,B,1)=B
GF(A,B,N)= GF(A,B,N-1)+GF(A,B,N-2) where N>1
给定3个非负数ABN返回除以的余数 1000000007
For example given A =3 B=4 n =5 the function should return 29 BECAUSE
GF(3,4,0)= 3 mod 1000000007 = 3
GF(3,4,1)= 4 mod 1000000007 = 4
GF(3,4,2)= (GF(3,4,0)+GF(3,4,1)) mod 1000000007 =7
GF(3,4,3)= (GF(3,4,1)+GF(3,4,2)) mod 1000000007 =11
GF(3,4,4)= (GF(3,4,2)+GF(3,4,3)) mod 1000000007 =18
GF(3,4,5)= (GF(3,4,3)+GF(3,4,4)) mod 1000000007 =29
空间复杂度O(N)时间O(Nlog N)
我正在寻找如何处理这个java伪代码或解决方案,我尝试了4到5小时,但无法前进,因此寻求你的帮助
谢谢