小编Lev*_*anu的帖子

EvolutionsComponents在编译时依赖注入游戏项目中

我试图了解如何使用编译时DI运行演变.

import play.api.ApplicationLoader.Context
import play.api.cache.EhCacheComponents
import play.api.mvc.EssentialFilter
import play.api.routing.Router
import play.api._
import play.api.db.evolutions.{ DynamicEvolutions, EvolutionsComponents}
import play.filters.gzip.GzipFilter
import router.Routes

class AppLoader extends ApplicationLoader  {
  override def load(context: Context): Application = {
    LoggerConfigurator(context.environment.classLoader).foreach(_.configure(context.environment))
    new AppComponents(context).application
  }


}

class AppComponents(context: Context) extends BuiltInComponentsFromContext(context) with EhCacheComponents with EvolutionsComponents {

  lazy val applicationController = new controllers.Application(defaultCacheApi)
  lazy val usersController = new controllers.Users(defaultCacheApi)
  lazy val assets = new controllers.Assets(httpErrorHandler)

  applicationEvolutions

  // Routes is a generated class
  override def router: Router = new Routes(httpErrorHandler, applicationController, usersController, …
Run Code Online (Sandbox Code Playgroud)

scala playframework-evolutions playframework-2.5

2
推荐指数
1
解决办法
401
查看次数

包含未按预期运行的对象的映射Scala

试图了解基本的Scala概念.为什么这段代码没有编译?

 case class User(
               id: Int,
               firstName: String,
               lastName: String,
               age: Int,
               gender: Option[String])

object UserRepository {
 val users = Map
 ( 1 ->  User(1, "John", "Doe", 32, Some("male")),
   2 -> User(2, "Johanna", "Doe", 30, None)
   )
//def findById(id: Int): Option[User] = users
//def findAll = users.values
def getUsers() = { users }
}

for ((k,v) <- UserRepository.getUsers() ){
 println(v)
}
Run Code Online (Sandbox Code Playgroud)

错误:(25,42)值过滤器不是对象的成员cala.collection.immutable.Map for((k,v)< - UserRepository.getUsers()){

我期望val用户持有Map?

简单的地图工作正常:

val simpleMap = Map (1 -> "First", 2 -> "Second")

for ((k,v) <- …
Run Code Online (Sandbox Code Playgroud)

dictionary scala object

1
推荐指数
1
解决办法
98
查看次数