小编Ale*_*nes的帖子

mysql_close()期望参数1为resource,给定null

造成错误的一行就是这一行......

mysql_close($con);
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这是整个代码......

$con=mysqli_connect("localhost","root","pass","db_name");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM medicos");


    while($row = mysqli_fetch_array($result)) {
    echo '.....';
    }



    mysql_close($con);
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php parameters null

2
推荐指数
1
解决办法
2万
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null ×1

parameters ×1

php ×1