我有一个带有弹簧启动的Java Web应用程序
运行测试时我需要排除一些Java配置文件:
测试配置(测试运行时需要包含):
@TestConfiguration
@PropertySource("classpath:otp-test.properties")
public class TestOTPConfig { }
Run Code Online (Sandbox Code Playgroud)
生产配置(测试运行时需要排除):
@Configuration
@PropertySource("classpath:otp.properties")
public class OTPConfig { }
Run Code Online (Sandbox Code Playgroud)
测试类(使用显式配置类):
@RunWith(SpringRunner.class)
@SpringBootTest(classes = TestAMCApplicationConfig.class)
public class AuthUserServiceTest { .... }
Run Code Online (Sandbox Code Playgroud)
测试配置:
@TestConfiguration
@Import({ TestDataSourceConfig.class, TestMailConfiguration.class, TestOTPConfig.class })
@TestPropertySource("classpath:amc-test.properties")
public class TestAMCApplicationConfig extends AMCApplicationConfig { }
Run Code Online (Sandbox Code Playgroud)
也有课:
@SpringBootApplication
public class AMCApplication { }
Run Code Online (Sandbox Code Playgroud)
当测试运行时OTPConfig,我需要TestOTPConfig...
我该怎么做?
ar db "Defference $"
Run Code Online (Sandbox Code Playgroud)
有什么区别
mov dx,offset ar
Run Code Online (Sandbox Code Playgroud)
和
lea dx,ar
Run Code Online (Sandbox Code Playgroud)
我认为两者都在做同样的工作,但这两者之间有什么区别
我设法生成一个与QEMU 2.0.0 Ubuntu 14.04一起使用的最小引导扇区:
.code16
.global _start
_start:
cli
mov $msg, %si
mov $0x0e, %ah
loop:
lodsb
or %al, %al
jz halt
int $0x10
jmp loop
halt:
hlt
msg:
.asciz "hello world"
.org 510
.word 0xaa55
Run Code Online (Sandbox Code Playgroud)
编译:
as -o main.o main.S
ld --oformat binary -o main.img -Ttext 0x7C00 main.o
Run Code Online (Sandbox Code Playgroud)
这个例子可以在这个回购中找到:https://github.com/cirosantilli/x86-bare-metal-examples/tree/2b79ac21df801fbf4619d009411be6b9cd10e6e0/no-ld-script
一旦:
qemu -hda main.img
Run Code Online (Sandbox Code Playgroud)
它hello world按预期在模拟器屏幕上显示.
但是,如果我尝试刻录到USB:
sudo dd if=main.img of=/dev/sdb
Run Code Online (Sandbox Code Playgroud)
然后将USB插入ThinkPad T400或T430,点击F12,然后选择我观察到的USB:
我也用Ubuntu 14.04映像测试了相同的USB,它启动正常,因此USB工作正常.
我应该如何更改此示例,以便它将在硬件上启动并显示hello world消息?
Ubuntu图像和我创建的图像有什么区别?
这记录在哪里?
我已将sudo dmidecodeT400 …
我开发了一个高性能的 Cholesky分解程序,它应该在单个CPU上具有大约10.5 GFLOP的峰值性能(没有超线程).但是当我测试它的性能时,有一些我不明白的现象.在我的实验中,我通过增加矩阵维数N(从250到10000)来测量性能.
对于任何NI测试,我都希望性能(在GFLOP中)应保持在10.5左右.但是,如第一张图所示,在实验中间观察到显着的性能下降.
CPU频率和CPU温度见第2和第3图.实验在400年代结束.实验开始时温度为51度,CPU忙时迅速升至72度.之后,它慢慢增长到78度的最高点.CPU频率基本稳定,温度升高时不下降.
所以,我的问题是:
CPU信息
System: Ubuntu 14.04 LTS
Laptop model: Lenovo-YOGA-3-Pro-1370
Processor: Intel Core M-5Y71 CPU @ 1.20 GHz * 2
Architecture: x86_64
CPU op-mode(s): 32-bit, 64-bit
Byte Order: Little Endian
CPU(s): 4
On-line CPU(s) list: 0,1
Off-line CPU(s) list: 2,3
Thread(s) per core: 1
Core(s) per socket: 2
Socket(s): 1
NUMA node(s): 1
Vendor ID: GenuineIntel
CPU family: 6
Model: 61
Stepping: 4
CPU MHz: 1474.484
BogoMIPS: 2799.91
Virtualisation: …Run Code Online (Sandbox Code Playgroud) 将.has-error重命名为.has-danger.
但是,这似乎不起作用.边框和文字尚未着色.
例如:
<div class="form-group has-danger">
<label class="form-control-label" for="inputDanger1">Input with danger</label>
<input type="text" class="form-control form-control-danger" id="inputDanger1">
<div class="form-control-feedback">Sorry, that username's taken. Try another?</div>
<small class="form-text text-muted">Example help text that remains unchanged.</small>
</div>
Run Code Online (Sandbox Code Playgroud)
演示:
I'm an occasional C programmer. I've come across this bit of inline assembly code in a Turbo C program
#define ADC(dst,src) { asm MOV AX, dst; asm ADD AX, src; \
asm ADC AX, 0; asm MOV dst, AX; }
Run Code Online (Sandbox Code Playgroud)
dst and src are both unsigned 16-bit integers.
It won't compile in GNU C++. Could someone please explain what it's doing? TIA!
表现:
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".AlarmActivity"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
</intent-filter>
</activity>
<receiver android:name="CallReciver">
<intent-filter>
<action android:name="android.intent.action.PHONE_STATE">
</action>
</intent-filter>
</receiver>
<receiver android:name=".SmsReceiver">
<intent-filter android:priority="1000">
<action android:name=
"android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
<receiver android:name=".OnBootReceiver">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
</receiver>
<service
android:enabled="true"
android:name=".AlarmService">
</service>
</application>
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED">
</uses-permission>
<uses-permission android:name="android.permission.READ_PHONE_STATE">
</uses-permission>
<uses-permission android:name="android.permission.WRITE_SMS">
</uses-permission>
<uses-permission android:name="android.permission.READ_SMS">
</uses-permission>
<uses-permission android:name="android.permission.SEND_SMS">
</uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS">
</uses-permission>
<uses-permission android:name="android.permission.INTERNET">
</uses-permission>
Run Code Online (Sandbox Code Playgroud)
接收器:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.util.Log;
import android.widget.Toast;
public class OnBootReceiver extends …Run Code Online (Sandbox Code Playgroud) 我正在为学习目的编写一个玩具内核,我遇到了一些麻烦.我做了一个简单的引导加载程序,从软盘加载一个段(用32位代码写入),然后引导加载程序启用A20门并打开保护模式.如果我用汇编程序写它,我可以跳到32位代码,但是如果我用C语言写它,我会得到一个三重错误.当我反汇编C代码时,我可以看到前两条指令涉及设置一个新的堆栈帧.这是工作ASM代码和失败的C代码之间的关键区别.我使用NASM v2.10.05作为ASM代码,使用来自DJGPP 4.72集合的GCC作为C代码.
这是引导加载程序代码:
org 7c00h
BITS 16
entry:
mov [drive], dl ;Save the current drive
cli
mov ax,cs ; Setup segment registers
mov ds,ax ; Make DS correct
mov ss,ax ; Make SS correct
mov bp,0fffeh
mov sp,0fffeh ;Setup a temporary stack
sti
;Set video mode to text
;===================
mov ah, 0
mov al, 3
int 10h
;===================
;Set current page to 0
;==================
mov ah, 5
mov al, 0
int 10h
;==================
;Load the sector
;=============
call load_image …Run Code Online (Sandbox Code Playgroud) 我正在努力测试受Spring Security保护的URL的访问控制.
配置如下所示:
http
.authorizeRequests()
.antMatchers("/api/user/**", "/user").authenticated()
.antMatchers("/api/admin/**", "/templates/admin/**", "/admin/**").hasAuthority("ADMIN")
.anyRequest().permitAll();
Run Code Online (Sandbox Code Playgroud)
测试类看起来像这样:
package com.kubukoz.myapp;
import com.kubukoz.myapp.config.WebSecurityConfig;
import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.test.SpringApplicationConfiguration;
import org.springframework.security.web.FilterChainProxy;
import org.springframework.test.context.ActiveProfiles;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import org.springframework.test.context.transaction.TransactionConfiguration;
import org.springframework.test.context.web.WebAppConfiguration;
import org.springframework.test.web.servlet.MockMvc;
import org.springframework.test.web.servlet.setup.MockMvcBuilders;
import org.springframework.web.context.WebApplicationContext;
import javax.transaction.Transactional;
import static org.springframework.test.web.servlet.request.MockMvcRequestBuilders.get;
import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status;
@RunWith(SpringJUnit4ClassRunner.class)
@SpringApplicationConfiguration(classes = {MyApplication.class, WebSecurityConfig.class})
@WebAppConfiguration
@TransactionConfiguration(defaultRollback = true)
@Transactional(rollbackOn = Exception.class)
public class MyApplicationTests {
@Autowired
private WebApplicationContext context;
private MockMvc mockMvc;
@Autowired
private FilterChainProxy filterChainProxy;
@Before
public void …Run Code Online (Sandbox Code Playgroud) 我试图在nasm中创建一个应该显示该字母的简单程序a.然而,它给了我一个Segfault并说:
./a.out: Symbol `printf' causes overflow in R_X86_64_PC32 relocation
Segmentation fault (core dumped)
Run Code Online (Sandbox Code Playgroud)
基本上,我试图将值0x61(字母a的十六进制)移动到内存地址1234,然后将其作为参数传递给printf.这是我的确切代码:
extern printf
section .text
global main
main:
push rbp
mov rax,0
mov qword [1234], 0x61 ; move 0x61 into address 1234
mov rdi, qword [1234] ; mov address 1234 into rdi
call printf ; should print the letter a
pop rbp
mov rax,0
ret
Run Code Online (Sandbox Code Playgroud)
我正在运行Linux x86_64