我得到了这个json和created_time
值显示整数格式的时间而不是时间格式,但我希望这个created_time以适当的格式.如何以正确的格式获取created_time?
"filter"=>"Normal",
"created_time"=>"1421677966",
"link"=>"http://instagram.com/p/yCfw5sKorK/",
"likes"=>{
"count"=>1,
"data"=>[
{
"username"=>"nikhil.thombare",
"profile_picture"=>"https://instagramimages-a.akamaihd.net/profiles/anonymousUser.jpg",
"id"=>"1651917721",
"full_name"=>"Nikhil Narendra Thombare"
}
]
Run Code Online (Sandbox Code Playgroud) 我正在使用9图像视图我想要随机设置图像到imageview,当我点击刷新按钮,但我尝试这样它是为图像的随机分配工作,但它一次在两个(或)三个imageview中重复相同的图像.我的代码中的问题在哪里..
final int[] imageViews = {
R.id.imgview11, R.id.imgview12, R.id.imgview13,
R.id.imgview21, R.id.imgview22, R.id.imgview23,
R.id.imgview31, R.id.imgview32, R.id.imgview33 };
final int[] images = {
R.drawable.i1, R.drawable.i2, R.drawable.i3,
R.drawable.i4, R.drawable.i5, R.drawable.i6,
R.drawable.i7, R.drawable.i8, R.drawable.empty };
final ImageButton shuffle = (ImageButton) findViewById(R.id.new_puzzle);
shuffle.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Random generator = new Random();
//int n = 9;
//n = generator.nextInt(n);
//Random random = new Random(System.currentTimeMillis());
for(int v : imageViews) {
ImageView iv = (ImageView)findViewById(v);
iv.setImageResource(images[generator.nextInt(images.length - 1)]);
}
}
});
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我不想重复,一个图像仅适用于一个imageview ..