小编Tas*_*man的帖子

我有我的目录结构

??? digitalocean
    ??? README.md
    ??? play.yml
    ??? roles
        ??? bootstrap_server
        ?   ??? tasks
        ?       ??? main.yml
        ??? create_new_user
        ?   ??? tasks
        ?       ??? main.yml
        ??? update
        ?   ??? tasks
        ?       ??? main.yml
        ??? vimserver
            ??? files
            ?   ??? vimrc_server
            ??? tasks
                ??? main.yml

当我在角色下创建用户时create_new_user,我将用户名硬编码为

---
- name: Creating a user named username on the specified web server.
  user: 
    name: username
    state: present
    shell: /bin/bash
    groups: admin
    generate_ssh_key: yes
    ssh_key_bits: 2048
    ssh_key_file: .ssh/id_rsa

- name: Copy .ssh/id_rsa from …

我正在练习不同的方法来为结构变量赋值.但是,当我尝试这个时,我得到了一些垃圾价值.这是代码.

#include<iostream>
using namespace std ;

struct Distance{
    int feet ;
    int inches;
};

void get_val(Distance );               
void disp(Distance);

int main(){

    Distance l, m ;                   //Objects 
    get_val(l);
    get_val(m);
    disp(l);
    disp(m);
    return 0  ;
}

void get_val(Distance length){
    cout<<"\nEnter Length "
        <<"\nFeet  : ";
    cin>>length.feet;
    cout<<"\nInches : ";
    cin>>length.inches;
}
void disp(Distance length){
    cout<<"\nLength : \n"
        <<"Feet : "<<length.feet
        <<"\nInches : "<<length.inches ;
}

为什么我将垃圾值作为输出？

我正在尝试使用以下命令更改运行 centos 的 docker 容器的主机名

hostnamectl set-hostname test.ovirt.org

但它给了我一个回溯

Could not set property: Failed to execute program /lib64/dbus-1/dbus-daemon-launch-helper: Success

退出代码为 1。

这是相关的 travis-CI 构建回溯

• https://travis-ci.org/rhevm-qe-automation/ovirt-ansible/jobs/242733186#L6181-L6210

编辑：

我正在运行命令来更改 Travis 构建中 ansible 任务内的主机名。使用交互模式编辑主机名不是一个选项。

我试图为我的S3存储桶创建一个远程后端。

provider "aws" {
  version = "1.36.0"
  profile = "tasdik"
  region  = "ap-south-1"
}

terraform {
  backend "s3" {
    bucket = "ops-bucket"
    key    = "aws/ap-south-1/homelab/s3/terraform.tfstate"
    region = "ap-south-1"
  }
}

resource "aws_s3_bucket" "ops-bucket" {
  bucket = "ops-bucket"
  acl    = "private"

  versioning {
    enabled = true
  }

  lifecycle {
    prevent_destroy = true
  }

  tags {
    Name       = "ops-bucket"
    Environmet = "devel"
  }
}

我尚未执行任何操作，到目前为止，该存储桶尚不存在。因此，terraform要求我做一个init。但是当我尝试这样做时，我得到了

$ terraform init       

Initializing the backend...

Successfully configured the backend "s3"! Terraform will automatically
use …

我正在浏览谷歌的python介绍并且遇到了s * 3比在类型的s + s + s地方更快的声明.sstring

出现这种情况的原因是什么？

我用Google搜索并发现python中的s + ='a'或s = s +'a'更快.但这没有帮助

尝试运行命令时,我得到了这个奇怪的letsencrypt错误

$ certbot certonly --standalone --email example@gmail.com --agree-tos -n -d trumporate.com,www.trumporate.com
Saving debug log to /var/log/letsencrypt/letsencrypt.log
Obtaining a new certificate
Performing the following challenges:
tls-sni-01 challenge for trumporate.com
tls-sni-01 challenge for www.trumporate.com
Waiting for verification...
Cleaning up challenges
Failed authorization procedure. trumporate.com (tls-sni-01): urn:acme:error:connection :: The server could not connect to the client to verify the domain :: Timeout, www.trumporate.com (tls-sni-01): urn:acme:error:connection :: The server could not connect to the client to verify the domain :: Timeout

IMPORTANT NOTES:
 - …

us-west1-a我正在尝试使用as区域中storage-class的terraform 创建一个 gcs 存储桶REGIONAL。但这样做时我收到此错误

* google_storage_bucket.terraform-state: 1 error(s) occurred:

* google_storage_bucket.terraform-state: googleapi: Error 400: The combination of locationConstraint and storageClass you provided is not supported for your project, invalid

这是.tf我现在拥有的文件

resource "google_storage_bucket" "terraform-state" {
  name          = "terraform-state"
  storage_class = "${var.storage-class}"
}

provider "google" {
  credentials = "${file("${path.module}/../credentials/account.json")}"
  project     = "${var.project-name}"
  region      = "${var.region}"
}

variable "region" {
  default = "us-west1" # Oregon
}

variable "project-name" {
  default = "my-project"
}

variable "location" { …

#include<iostream>
using namespace std ; 
class Foo{
    int a , b ;
public:
    Foo(int x, int y){
        a = x ;
        b = y  ;
    }
    Foo(Foo& obj){
        a = obj.a ;
        b = obj.b ;
    }
};

int main(){
    Foo obj(2,3) ;
    Foo obj1(obj) ;
    Foo obj2 = obj ;
}

如果我是正确的,都Foo obj2 = obj ;和Foo obj1(obj) ;调用拷贝构造函数.

使用其中一个的优点和缺点是什么？

我有类似的东西

stud_1 = {'stud_2' : 1, 'stud_3' : 3, 'stud_4' : 2,'stud_5' : 5,'stud_6' : 1,'stud_7' : 3,'stud_8' : 4,'stud_9' : 3}
stud_2 = {'stud_1' : 3, 'stud_3' : 2, 'stud_4' : 4,'stud_5' : 2,'stud_6' : 1,'stud_7' : 5,'stud_8' : 1,'stud_9' : 2}
stud_3 = {'stud_1' : 1, 'stud_2' : 5, 'stud_4' : 3,'stud_5' : 5,'stud_6' : 5,'stud_7' : 2,'stud_8' : 3,'stud_9' : 5}
stud_4 = {'stud_1' : 4, 'stud_2' : 3, 'stud_3' : 2,'stud_5' : 1,'stud_6' : 5,'stud_7' : …

为什么这个论点不是通过价值传递的？

当我尝试它时,我的编译器只给了我一条消息,说"你可能意味着" Foo(const Foo&).

这是什么原因？