小编use*_*415的帖子

我目前正在使用console.neo4j.org上的示例数据编写一个输出分层JSON的查询.

使用创建示例数据

create (Neo:Crew {name:'Neo'}), (Morpheus:Crew {name: 'Morpheus'}), (Trinity:Crew {name: 'Trinity'}), (Cypher:Crew:Matrix {name: 'Cypher'}), (Smith:Matrix {name: 'Agent Smith'}), (Architect:Matrix {name:'The Architect'}),
(Neo)-[:KNOWS]->(Morpheus), (Neo)-[:LOVES]->(Trinity), (Morpheus)-[:KNOWS]->(Trinity),
(Morpheus)-[:KNOWS]->(Cypher), (Cypher)-[:KNOWS]->(Smith), (Smith)-[:CODED_BY]->(Architect)

理想的输出如下

name:"Neo"
children: [
  { 
    name: "Morpheus",
    children: [
      {name: "Trinity", children: []}
      {name: "Cypher", children: [
        {name: "Agent Smith", children: []}
      ]}
    ]
  }
]
}

现在,我正在使用以下查询

MATCH p =(:Crew { name: "Neo" })-[q:KNOWS*0..]-m
RETURN extract(n IN nodes(p)| n)

得到这个

[(0:Crew {name:"Neo"})]
[(0:Crew {name:"Neo"}), (1:Crew {name:"Morpheus"})]
[(0:Crew {name:"Neo"}), (1:Crew {name:"Morpheus"}), (2:Crew {name:"Trinity"})] …