小编Sym*_*ans的帖子

这让我疯了好几个小时了.

在perl中考虑以下测试脚本:(hello.pl)

#!/usr/bin/perl
print "----------------------------------\n";
$numArgs = $#ARGV + 1;
print "thanks, you gave me $numArgs command-line arguments:\n";

foreach $argnum (0 .. $#ARGV) {
    print "$ARGV[$argnum]\n";
}

好吧,它只是打印出给脚本的命令行参数.

例如:

$ ./hello.pl apple pie
----------------------------------
thanks, you gave me 2 command-line arguments:
apple
pie

我可以通过用双引号括起来给脚本一个带空格的参数:

$ ./hello.pl "apple pie"
----------------------------------
thanks, you gave me 1 command-line arguments:
apple pie

现在我想在shell脚本中使用这个脚本.我已经设置了这样的shell脚本:

#!/bin/bash

PARAM="apple pie"
COMMAND="./hello.pl \"$PARAM\""

echo "(command is $COMMAND)"
$COMMAND

我用相同的参数调用hello.pl并转义引号.该脚本返回:

$ ./test.sh 
(command is ./hello.pl "apple pie")
----------------------------------
thanks, you …