小编muo*_*i_D的帖子

有人可以给我发送下载此文件的直接链接:poi-3.10-FINAL-20140208.jar？我只看到互联网上的.zip文件,而不是.jar文件.

我遇到了一个排球问题,其中一个请求有时被命中两次到服务器,结果,这几乎弄乱了我的代码逻辑.有没有办法可以将请求数量限制为1？我尝试过做这里解释的问题但有时问题仍然存在

我试图使用此文档https://stripe.com/docs/mobile/android/customer-information在android中使用条带SDK实现上述结帐流程.我已经创建了一个后端调用,它会像这样返回短暂的密钥

{
    "id": "ephkey_EPHEMERAL_KEY_HERE",
    "object": "ephemeral_key",
    "associated_objects": [
        {
            "id": "cus_CUSTOMER_ID_HERE",
            "type": "customer"
        }
    ],
    "created": 1535352558,
    "expires": 1535356158,
    "livemode": true,
    "secret": "ek_live_SECRET_HERE"
}

在我的应用程序中,我正在初始化我的CustomerSession并启动PaymentMethodsActivity

CustomerSession.initCustomerSession(
                new MyEphemeralKeyProvider(
                        new MyEphemeralKeyProvider.ProgressListener() {
                            @Override
                            public void onStringResponse(String string) {

                                if (string.startsWith("Error: ")) {
                                    new android.support.v7.app.AlertDialog.Builder(SelectCardActivity.this).setMessage(string).show();
                                }

                                Intent payIntent = PaymentMethodsActivity.newIntent(SelectCardActivity.this);
                                startActivityForResult(payIntent, REQUEST_CODE_SELECT_SOURCE);
                            }
                        }));

然后我有这个onActivityResult方法

  @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        if (requestCode == REQUEST_CODE_SELECT_SOURCE && resultCode == RESULT_OK) {
            String selectedSource = …

我正在创建一个带有laravel的REST api,允许用户从他们的Android设备中选择一个图像文件,然后将其上传到服务器.在将图像与其他参数一起发送到服务器之前,该图像将转换为base64.我想将此base64转换为文件并将其存储在服务器上,然后生成可用于访问它的链接.这是我到目前为止所尝试的,它不起作用:我已经创建了一个存储符号链接

public function create(Request $request)
{
        $location = new Location();
        $location->name = $request->location_name;
        $location->latitude = $request->latitude;
        $location->longitude = $request->longitude;

        $location->saveOrFail();

        $provider = new Provider();
        $provider->name = $request->provider_name;
        $provider->location_id = $location->id;
        $provider->category_id = $request->category_id;
        $provider->description = $request->description;
        $provider->image = request()->file(base64_decode($request->encoded_image))->store('public/uploads');


        $provider->saveOrFail();

        return json_encode(array('status'=>'success', 'message'=>'Provider created successfully'));


}

我正在尝试创建一个空白数组,以便我可以用循环中从数据库中获取的值填充它.这是我的代码:

$stmt = $conn->prepare("SELECT * FROM users WHERE username = ? AND password = ?");
$stmt->bind_param("ss", $username, $password);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($id, $name, $email, $username, $password);

$user = array[];

        while($stmt->fetch)
        {
            $user[name] = $name;
            $user[email] = $email;
            $user[username] = $username;
            $user[password] = $password;
        }

但它给了我这个错误

解析错误:语法错误,意外'[',期待'('在第26行的/home/cardplan/public_html/android/FetchUserData.php中

第26行就是这一行

 $user = array[];