我重载了一个cout和cin opeartor,当我尝试使用它时,它给了我一个像这样的错误:
1 IntelliSense: function "std::basic_ostream<_Elem, _Traits>::basic_ostream(const std::basic_ostream<_Elem, _Traits>::_Myt &)
[with _Elem=char, _Traits=std::char_traits<char>]"
(declared at line 84 of "C:\Program Files (x86)\Microsoft Visual Studio 12.0\VC\include\ostream") cannot be referenced -- it is a deleted function
这是我班级的头文件:
#pragma once
#include <iostream>
class Point2D
{
private:
int m_X;
int m_Y;
public:
Point2D(): m_X(0), m_Y(0)
{
}
Point2D(int x, int y): m_X(x), m_Y(y)
{
}
friend std::ostream& operator<< (std::ostream out, const Point2D &point)
{
out << "(" << point.m_X << "," << point.m_Y << ")" …我正在重载类型转换操作符,并在Visual Studio 2013中发生内部错误.
这是指数类的标题:
#pragma once
#include "Calc.h"
#include <iostream>
using namespace std;
class Exponent
{
private:
int base;
int exponent;
public:
Exponent();
Exponent(int a)
{
base = a;
}
int getBase()
{
return base;
}
};
void printExp(Exponent e)
{
cout << e.getBase() << endl;
}
这是calc.h我写的将包含重载类型转换函数:
#pragma once
#include "Exponent.h"
class Calc
{
private:
int acc;
public:
Calc();
Calc(int a);
operator Exponent() //this is where I get an error.
{
return Exponent(acc);
}
};
这是主要功能:
#include "stdafx.h"
#include …因此,我的程序基本上是创建Main的子线程并从用户获得一个整数作为输入,并通过将其计数为1000将该数字转换为milisecond.
但是在for循环中,当我输入数字5作为输入时,Thread.Sleep()会休眠大约10秒.
代码:
static void CallToChildThread()
{
Console.WriteLine("How many seconds do you want this thread to rest?");
int time = Convert.ToInt32(Console.Read());
int mili = time * 1000;
for (int i = 0; i < time; i++)
{
Console.Write(". ");
Thread.Sleep(mili);
}
Console.WriteLine();
}
因此,当我键入5时,代码将乘以5乘以1000并将5000存储在mili中.
但是,在for循环中,当执行Thread.Sleep(mili)时,它不会整整睡5秒,它会在循环中迭代一次后休眠10秒.
此外,当我用5000更改替换mili以使线程休眠5秒时,每次循环,并且它工作,但循环迭代超过我的预期.例如,这是我输入的输入:
How many seconds do you want this thread to rest?
5
. . . . . . . . . .
每次迭代时它都会正常计算5秒.但它迭代超过5.如果我键入5然后不应该for循环迭代5次并中止？只显示5个时期？