用php和mysql显示html问题
嗨基本上我有一个快速的mysql_fetch_array脚本来显示db中的内容,如下所示:
$sql_select_jobs = $db->query("SELECT * FROM `probid_jobs`");
while ($jobs_found = $db->fetch_array($sql_select_jobs)) {
$template_output .= "<div class=\"listed-jobs\" style=\"border: 1px solid gray; border-bottom: 0px; padding: 20px;\">";
$template_output .= "Job Title: " . $jobs_found['job_title'] . "<br />";
$template_output .= "Location: " . $jobs_found['location'] . "<br />";
$template_output .= "Salary: " . $jobs_found['salary'] . "<br />";
$template_output .= "Date Posted: " . $jobs_found['date'] . "<br /><br />";
$template_output .= "Description: " . $jobs_found['description'] . "...<a href=\"\">more</a><br />";
$template_output .= "</div>";
}
但是输出看起来像这样:
Job …