小编mbu*_*enc的帖子

我正在尝试将Socialite包实现到我的项目中.这是我的代码,工作正常.但是,如果用户注销尝试重新登录,它会在数据库中重复输入.此外,我无法使用$ userData-> name获取用户的公共名称.它返回null.

这是我的控制器;

namespace App\Http\Controllers;

use App\AuthenticateUser;
use App\AuthenticateUserListener;
use App\Http\Requests;
use Illuminate\Http\Request;

class SocialLoginsController extends Controller implements 
AuthenticateUserListener
{
/**
 * @param AuthenticateUser $authenticateUser
 * @param Request $request
 * @return \Symfony\Component\HttpFoundation\RedirectResponse
 */
public function socialLogin(AuthenticateUser $authenticateUser, Request $request)
{
    $hasCode = $request->has('code');
    return $authenticateUser->execute($hasCode, $this);
}


/**
 * When a user has successfully been logged in...
 *
 * @param $user
 * @return \Illuminate\Routing\Redirector
 */
public function userHasLoggedIn($user)
{
    return redirect('student');
}

我的用户存储库;

namespace App\Repositories;
use App\User;


class UserRepository …

我正在尝试制作一个用户可以轻松更改密码的表单.我希望我的逻辑是正确的,但是我得到的错误如下;

Expected argument of type "string", "AppBundle\Form\ChangePasswordType" given

这是我的控制器;

public function changePasswdAction(Request $request)
{
    $changePasswordModel = new ChangePassword();
    $form = $this->createForm(new ChangePasswordType(), $changePasswordModel);

    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        // perform some action,
        // such as encoding with MessageDigestPasswordEncoder and persist
        return $this->redirect($this->generateUrl('homepage'));
    }

    return $this->render(':security:changepassword.html.twig', array(
        'form' => $form->createView(),
    ));
}

这是我的模特;

class ChangePassword
{

/**
 * @SecurityAssert\UserPassword(
 *     message = "Wrong value for your current password"
 * )
 */
protected $oldPassword;

/**
 * @Assert\Length(
 *     min = 6, …