小编hel*_*n.h的帖子

根据另一列的条件删除在一列中重复的行

这是我的数据集的一个例子;

Date      Time(GMT)Depth Temp  Salinity Density Phosphate
24/06/2002  1000    1           33.855          0.01
24/06/2002  1000    45          33.827          0.01
01/07/2002  1000    10  13.26   33.104  24.873  0.06
01/07/2002  1000    30  12.01   33.787  25.646  0.13
08/07/2002  1000    5   13.34   33.609  25.248  0.01
08/07/2002  1000    40  12.01   34.258  26.011  1.33
15/07/2002  1000    30  12.04   34.507  26.199  0.01
22/07/2002  1000    5   13.93   33.792  25.269  0.01
22/07/2002  1000    30  11.9    34.438  26.172  0.08
29/07/2002  1000    5   13.23   34.09   25.642  0.01
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我想删除重复的行,这样我每个日期只有一行,我想根据深度做这个,我想保持最深(最深)的行.有任何想法吗?

r date duplicate-removal

27
推荐指数
4
解决办法
4万
查看次数

有没有办法缩短一系列colClasses

目前我正在读取这样的数据文件:

setwd("N:/HH Scallop Growth Project/Ring data by cruise/")

growth <- read.csv("Growth.csv",sep=",",header=TRUE,
                    colClasses=c("character","character","character","numeric",
                                 "character","numeric","numeric","numeric",
                                 "numeric","numeric","numeric","numeric",
                                 "numeric","numeric","character","numeric",
                                 "character","numeric","numeric","numeric",
                                 "numeric","character","numeric","numeric",
                                 "numeric")) 
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它工作正常,但它有点长/邋,,有没有办法缩短/分组colClasses

r

5
推荐指数
1
解决办法
128
查看次数

读取并绑定多个csv文件

我有一系列csv文件(每个anum一个),具有相同的列标题和不同的行数.最初我正在阅读它们并将它们合并;

setwd <- ("N:/Ring data by cruise/Shetland")
LengthHeight2013 <- read.csv("N:/Ring data by      cruise/Shetland/R_0113A_S2013_WD.csv",sep=",",header=TRUE)
LengthHeight2012 <- read.csv("N:/Ring data by cruise/Shetland/R_0212A_S2012_WD.csv",sep=",",header=TRUE)
LengthHeight2011 <- read.csv("N:/Ring data by cruise/Shetland/R_0211A_S2011_WOD.csv",sep=",",header=TRUE)
LengthHeight2010 <- read.csv("N:/Ring data by cruise/Shetland/R_0310A_S2010_WOD.csv",sep=",",header=TRUE)
LengthHeight2009 <- read.csv("N:/Ring data by cruise/Shetland/R_0309A_S2009_WOD.csv",sep=",",header=TRUE)

LengthHeight <- merge(LengthHeight2013,LengthHeight2012,all=TRUE)
LengthHeight <- merge(LengthHeight,LengthHeight2011,all=TRUE)
LengthHeight <- merge(LengthHeight,LengthHeight2010,all=TRUE)
LengthHeight <- merge(LengthHeight,LengthHeight2009,all=TRUE)
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我想知道是否有更短/更整洁的方法来做到这一点,同时考虑到每次运行脚本时我可能想要查看不同的年份.

我也发现Tony Cookson的这段代码看起来会像我想要的那样,但它为我生成的数据框只有正确的标题但没有数据行.

multmerge = function(mypath){
filenames=list.files(path=mypath, full.names=TRUE)
datalist = lapply(filenames, function(x){read.csv(file=x,header=T)})
Reduce(function(x,y) {merge(x,y)}, datalist)

mymergeddata = multmerge("C://R//mergeme")
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csv data-binding merge r dataframe

5
推荐指数
2
解决办法
1万
查看次数

ggplot 指定经度/纬度轴中断

我使用以下代码从 shapefile 创建一个“Trial_area”的地图,并覆盖第二个 shapefile 中的海岸线和“prod_areas”。然后,我使用 coord_sf 将地图缩放到试验区域多边形的 st_bbox。但是,对于某些区域(参见下面的示例),轴刻度文本标签最终会重叠,有没有办法可以指定轴刻度线间隔以避免这种情况(例如,纬度为 0.1,经度为 0.5)?

poly <- trial_areas %>% 
filter(Id==5) 
ext <- st_bbox(poly)

plot_SoundOfSleat <- ggplot() +
theme(panel.background = element_rect(fill = 'light blue'),element_line()) +
geom_sf(data=poly)+
geom_sf(data=prod_areas,fill=mycol) +
geom_sf(data = Scot, aes(),
        fill = "lightgreen",col="darkgreen") +
coord_sf(xlim = c(ext[1], ext[3]), ylim = c(ext[2], ext[4]))  +
ggtitle("Sound of Sleat Trial Area 5") +
geom_sf_text(aes(label = Producti_1), data=prod_areas,size=3,hjust=0, vjust=0) +
labs(x = "Longitude", y= "Latitude")

plot_SoundOfSleat
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在此输入图像描述

r

4
推荐指数
1
解决办法
2531
查看次数

r删除不符合子集标准的行

我已经对我的df进行了攻击,为渔业区域和不同的渔具和物种制作了一系列着陆(重量)时间序列.我想删除每个捕鱼区域的所有行+渔具+ Species.Code组合,其中时间序列的平均着陆重量小于10吨.

这是我的代码的一个例子(每个组合的年份范围并不总是相同);

    Year   Species.Code gear        region  Landings.t
    1988    COD         creel       Greece  1
    1992    COD         creel       Greece  2
    1994    COD         creel       Greece  1
    1996    COD         creel       Greece  2
    2001    COD         creel       Greece  1
    2002    COD         creel       Greece  1
    2003    COD         creel       Greece  1
    1984    LOB         creel       Cyprus  24
    1985    LOB         creel       Cyprus  18
    1986    LOB         creel       Cyprus  21
    1987    LOB         creel       Cyprus  10
    1988    LOB         creel       Cyprus  38
    1989    LOB         creel       Cyprus  35
    1990    LOB         creel       Cyprus  29
    1991    LOB …
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grouping r subset

0
推荐指数
1
解决办法
287
查看次数

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r ×5

csv ×1

data-binding ×1

dataframe ×1

date ×1

duplicate-removal ×1

grouping ×1

merge ×1

subset ×1