小编jay*_*kar的帖子

我正在使用 Laravel 从事一个业余爱好项目（商店管理）。我正在尝试使用 DB::beginTransaction() 和 DB::rollback()，但它不起作用。根据我的代码，我认为数据库中不应该填充任何条目。

我已经用谷歌搜索过可能性，但找不到任何解决方案。而且，我的 MySQL 表是 InnoDB

这是我的商店控制器文件。

    class shopController extends Controller
{
    public function __construct()
    {
        $this->middleware('auth');
    }
    public function getView()
    {
        if(Auth::user()->shop_status==0)
            return View::make('shop')->with('name',json_encode(Auth::user()->Vendor_Detail()->get(['first_name', 'last_name'])));
        else
            return redirect('/home');
    }

    public function addShop(ShopDataRequest $request){
    //get the logged in vendor's model instance. Auth uses Vendor model
            $vendor = Auth::user();
    //create new Shop Model
            $shop = new Shop;
            $shop->name = $request['shop_name'];
            $shop->address = $request->addressLine1;
            $shop->pincode = $request->pincode;
            $shop->phone = $request->phone;
            $shop->shop_type = $request->shop_type;

        DB::beginTransaction();
        try{            
             //save shop details …

我有一个带有元信息的JSON响应

{"total":3594,"per_page":20,"current_page":18,"last_page":180,"next_page_url":"http:\/\/localhost:7777\/youtube\/public\/service\/category\/user_id\/education?page=19","prev_page_url":"http:\/\/localhost:7777\/app\/public\/test?page=17","from":341,"to":360

我需要删除并仅显示选定的结果数据..