该Chronos的网站提到的Chronos支持自定义Mesos执行人.Mesos示例显示如何编写自定义Mesos执行程序(master/src/examples/java/TestExecutor.java).但是,我无法找到有关如何通过Chronos RET API安排此类自定义执行程序的任何文档.任何关于此的帮助或指示将不胜感激.
提前致谢.
升级到OS X Mavericks后,make在我的Mesos构建目录中运行会导致错误:
google/protobuf/message.cc:130:60: error: implicit instantiation of undefined template 'std::__1::basic_istream<char, std::__1::char_traits<char> >'
return ParseFromZeroCopyStream(&zero_copy_input) && input->eof();
^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/c++/v1/iosfwd:108:28: note: template is declared here
class _LIBCPP_TYPE_VIS basic_istream;
^
google/protobuf/message.cc:135:67: error: implicit instantiation of undefined template 'std::__1::basic_istream<char, std::__1::char_traits<char> >'
return ParsePartialFromZeroCopyStream(&zero_copy_input) && input->eof();
^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/c++/v1/iosfwd:108:28: note: template is declared here
class _LIBCPP_TYPE_VIS basic_istream;
^
google/protobuf/message.cc:175:16: error: implicit instantiation of undefined template 'std::__1::basic_ostream<char, std::__1::char_traits<char> >'
return output->good();
^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../lib/c++/v1/iosfwd:110:28: note: template is declared here
class _LIBCPP_TYPE_VIS basic_ostream;
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我从一个干净的构建目录开始,重新运行./bootstrap并运行 …
我正在完成反应入门教程并遇到了我正在做的实验的问题.我能够记录一个对象,但在控制台中,我收到以下错误:
未捕获的TypeError:无法读取未定义的属性"结果"
我可以记录对象,所以我知道我的api调用成功,但由于某种原因,我的反应状态似乎没有得到更新.我认为我的渲染功能是在我的数据对象从API更新之前发生的,但不确定如何修复它.
<!doctype html>
<html>
<head>
<title>Weather Widget</title>
<link rel="stylesheet" href="weather.css" />
<script src="http://fb.me/react-0.10.0.js"></script>
<script src="http://fb.me/JSXTransformer-0.10.0.js"></script>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
</head>
<body>
<script type="text/jsx">
/*** @jsx React.DOM */
var weatherWidget = React.createClass({
loadData: function(){
$.ajax({
url: 'http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location%3D%2222102%22&format=json',
dataType : "jsonp",
cache: false,
success: function(data) {
console.log(data)
this.setState({data: data});
}.bind(this)
});
},
getInitialState: function(){
return {data: []};
},
componentWillMount: function(){
this.loadData();
},
render: function(){
return(
<div className="ww-container">
<div className="ww-current-condition">
<div className="ww-current-temperture">{this.state.data.query.results.channel.item.condition.temp}°</div>
</div>
</div>
)
}
});
React.renderComponent(<weatherWidget />, document.body);
</script>
</body> …Run Code Online (Sandbox Code Playgroud) 我正在学习ReactJS并尝试CRUD使用它来开发小型表单.此时,我正试图input values从其他sibling component设置执行更新.
所以,如果我click上edit button in first row的网格,Organzation Name并Description输入框应该得到"abc com"和"company Abc"值分别为.
var OrganizationHandler = React.createClass(
render: function() {
return (
<div>
<OrganizationAPP onOrganizationSubmit=this.handleOrganizationSubmit} />
<OrganizationList external_DeleteOrganization={this.DeleteOrganizationFromServer} data= {this.state.data} />
</div>
);
}
});
var OrganizationList = React.createClass({
internal_DeleteOrganization: function(id) {
this.props.external_DeleteOrganization(id);
},
render: function() {
var results = this.props.data;
var parsed_results = results.objects;
var that = this;
var organizations = …Run Code Online (Sandbox Code Playgroud) 我有2张这样的桌子,
表格1
Id Locations
-- ---------
1 India, Australia
2 US , UK
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表2
Table2Id Location
-------- --------
101 Italy
102 UK
103 Hungary
104 India
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我需要在条件内连接这两个表,如果Locations在table2中包含Locationtable1 中的 字段.结果就像
Id Table2Id Location Locations
-- -------- -------- ---------
1 104 India India, Australia
2 102 UK US , UK
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我试过类似的东西
Select t1.id,
t2.Table2Id,
t1.Locations,
t2.Location
From Table1 t1
Inner join Table2 t2 On CONTAINS(t1.Locations, t2.Location)
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但第二个参数contains应该是一个字符串.它不允许在那里给出列名.
我不能在查询中使用temptable或variable.因为此查询需要ExactTarget在不支持temptable和支持的电子邮件广告系列工具上运行 …
Chrome扩展程序的弹出窗口和选项页面有一个额外的用户代理样式表,可添加类似于Chrome自己chrome://settings和其他页面的样式.在解释如何声明V2选项页面时提到了样式:
chrome_style(boolean) - 可选
如果为true,则Chrome用户代理样式表将应用于您的选项页面.默认值为false,但我们建议您启用它以获得与Chrome一致的用户界面.
样式表是一个稳定的API吗?
样式表在哪里?
我有一个按钮,当我点击这个按钮时,我想渲染一个div并附加到它body.
当我再次单击此按钮时,div将呈现一个新的.
我想:我点击按钮多少次,div渲染多少次.
以下代码只能呈现一个div:(jsFiddle:http://jsfiddle.net/pw4yq/)
var $tool = document.getElementById('tool');
var $main = document.getElementById('main');
var partBox = React.createClass({displayName: 'partBox',
render: function(){
return (
React.DOM.div({className:"box"}, "HELLO! ", this.props.ts)
)
}
});
var createBoxBtn = React.createClass({displayName: 'createBoxBtn',
createBox: function(){
var timeStamp = new Date().getTime();
React.renderComponent(partBox( {ts:timeStamp} ), $main);
},
render: function(){
return (
React.DOM.button( {onClick:this.createBox}, "createBox")
)
}
});
React.renderComponent(createBoxBtn(null ), $tool);
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