小编Bug*_*ter的帖子

我在我的项目中实现搜索我想要的是在where子句中连接到列以从表中获取结果.

这是我在做的事情:

from django.db.models import Q

if 'search[value]' in request.POST and len(request.POST['search[value]']) >= 3:
    search_value = request.POST['search[value]'].strip()

    q.extend([
        Q(id__icontains=request.POST['search[value]']) |
        (Q(created_by__first_name=request.POST['search[value]']) & Q(created_for=None)) |
        Q(created_for__first_name=request.POST['search[value]']) |
        (Q(created_by__last_name=request.POST['search[value]']) & Q(created_for=None)) |
        Q(created_for__last_name=request.POST['search[value]']) |
        (Q(created_by__email__icontains=search_value) & Q(created_for=None)) |
        Q(created_for__email__icontains=search_value) |
        Q(ticket_category=request.POST['search[value]']) |
        Q(status__icontains=request.POST['search[value]']) |
        Q(issue_type__icontains=request.POST['search[value]']) |
        Q(title__icontains=request.POST['search[value]']) |
        Q(assigned_to__first_name__icontains=request.POST['search[value]']) |

    ])

现在我想添加另一个OR条件,如:

CONCAT(' ', created_by__first_name, created_by__last_name) like '%'search_value'%"

但是当我将这个条件添加到查询集时,它变为AND

where = ["CONCAT_WS(' ', profiles_userprofile.first_name, profiles_userprofile.last_name) like '"+request.POST['search[value]']+"' "]
            tickets = Ticket.objects.get_active(u, page_type).filter(*q).extra(where=where).exclude(*exq).order_by(*order_dash)[cur:cur_length]

如何将其转换为OR条件？

我想在添加/删除按钮的同时从父DOM元素添加/删除类，例如，如果我单击添加类按钮，则它将新的类名称“单击”添加到父div，并在单击删除类按钮时删除该类：

index.html

<div class="main-div">

  <div class="second-div" id="config">
  </div>

</div>

config.jsx

import React from 'react';
import ReactDOM from 'react-dom';
import Main from 'Main';

ReactDOM.render(
    <Main/>,
    document.getElementById('config')
);

Main.jsx

import ReactDOM from 'react-dom'
import React from "react";
import createReactClass from "create-react-class";


export default createReactClass({
    getInitialState() {
        return {
            show-main-div: false
    };
    },

    addClass() {
    // want to add new class on parent DOM element i.e <div class="main-div">
    },

    render: function () {
        return (
            <div>
                <button className="add-class" onClick={() => {this.addClass()}}>
                    Add Class …

当特定 URL 匹配时，我想跳过所有重写 URL。我想打开这个页面：

https://www.example.com/.well-known/pki-validation/godaddy.html

如果godaddy.html匹配 URL。这是我在做什么：

RewriteCond "%{REQUEST_URI}" "==/godaddy.html" 
RewriteRule ^(.*)$  https://www.example.com/.well-known/pki-validation/godaddy.html [L]
RewriteCond %{HTTP_HOST} ^example.com
RewriteRule ^(.*)$ https://www.example.com/index.php

但它不起作用。我也试过这个[END]标志，但是当我写标志时，[END]它给了我 500 个内部服务器错误。

我正在使用数据表，并且要在单击该行时删除选定的行。

这是datatabe的代码

$('.data-table').dataTable({
  "aaSorting": [],
  "oLanguage": {"sSearch": ""},
  "fnDrawCallback": function (oSettings) {}
});

这是删除功能...

<input type="button" class="btndel btn-primary btn btn-primary" onclick="                                                                  $(this).closest('tr').addClass('selected');
if ($('.tab1').hasClass('active')) {
  var rows = $('.data-table').dataTable().row('.selected').remove().draw();
  var xSum = 0;
  var items = document.getElementsByClassName('pp');
  var itemCount = items.length;
  var total = 0;
  $('.pp').each(function () {
  var che = isNaN($(this).text());
  if (che == false) {
    xSum += parseFloat($(this).text());
  }
});
var value1 = xSum / parseInt(itemCount);
$('#avgsold').text(value1.toFixed(2));
}
if ($('.tab2').hasClass('active')) {}" value="Delete" />

但这给了错误

未捕获的TypeError：$（...）。dataTable（...）。row不是函数

提前致谢