该表Arc(x,y)目前有以下元组(注意有重复):
(1,2),
(1,2),
(2,3),
(3,4),
(3,4),
(4,1),
(4,1),
(4,1),
(4,2)
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计算查询结果:
SELECT a1.x, a2.y, COUNT(*)
FROM Arc a1, Arc a2
WHERE a1.y = a2.x
GROUP BY a1.x, a2.y;
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是什么a1和a2指的是什么?
我有以下HTML结构:
<span class="spam">
<button class="spam_button" value="2">Spam</button>
</span>
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我想要在父级中显示响应,但我无法理解.
$('.spam_button').live('click', function() {
var spam_id =$(this).val();
$.ajax({
type: "POST",
url: "spam.php",
data: "spam_id="+spam_id,
success: function(html){
$(this).parent().html(html);
}
});
});
Run Code Online (Sandbox Code Playgroud) 这是我的jQuery
$('.vote_down').live('click', function() {
var $votes = $(this);
var c_id = $(this).closest('.c_id').val();
var c_vote = $(this).closest('.c_vote').val();
$.ajax({
type: "POST",
url: "votes.php",
data: "c_id="+c_id+"&c_vote="+c_vote,
success: function(html){
$votes.parent().html(html);
}
});
});
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以下是它的html:
vars c_id,c_vote目前一无所获
<div class="votes">
<input type="hidden" class="c_id" value="5" />
<input type="hidden" class="c_vote" value="2" />
<img src="down_vote.png" border="0" class="vote_down" alt="Down Vote" />
</div>
Run Code Online (Sandbox Code Playgroud) 这可以在 FF 上提交,但不能在 Chrome 上提交。有什么建议么?
<form action="/test" method="post" onchange="this.submit();">
<select>
<option value="f">f</option>
<option value="g">g</option>
</select>
</form>
Run Code Online (Sandbox Code Playgroud) 我已尝试过多种方法来使用全文查询进行过滤,但无济于事.这是我尝试过的:
{
"_source": "_id",
"query": {
"filtered": {
"multi_match": {
"query": "test search query",
"fields": ["title"]
},
"filter": {
"term": {"user_id": "1"}
}
}
}
}
Run Code Online (Sandbox Code Playgroud) 我有以下数组,无法弄清楚如何获取数据:
Array (
[0] => stdClass Object (
[address_components] => Array (
[0] => stdClass Object (
[long_name] => 180
[short_name] => 180
[types] => Array ( [0] => street_number )
)
[1] => stdClass Object (
[long_name] => Campus Dr
[short_name] => Campus Dr
[types] => Array ( [0] => route )
)
[2] => stdClass Object (
[long_name] => Arcadia
[short_name] => Arcadia
[types] => Array (
[0] => locality
[1] => political
)
)
[3] => stdClass …Run Code Online (Sandbox Code Playgroud)