当您运行:时kubectl get svc -n default
,您将已经有一个类型为ClusterIP的kubernetes服务。
这项服务的目的是什么?任何参考表示赞赏。
我在Minikube中跑步
xyz:Kubernetes _$ kubectl describe svc/kubernetes
Name: kubernetes
Namespace: default
Labels: component=apiserver
provider=kubernetes
Annotations: <none>
Selector: <none>
Type: ClusterIP
IP: 10.0.0.1
Port: https 443/TCP
TargetPort: 8443/TCP
Endpoints: 10.0.2.15:8443
Session Affinity: ClientIP
Events: <none>
xyz:Kubernetes _$ kubectl cluster-info
Kubernetes master is running at https://192.168.99.100:8443
Run Code Online (Sandbox Code Playgroud) 我计划在3个月内使用Play Framework构建生产就绪的应用程序.我应该从1.2.4或2.0开始.2.0有一些非常好的功能,但它处于测试阶段.
任何建议都会有帮助.谢谢
我使用以下设置:1. Docker 引擎:18.02.0-ce-rc1,2. Compose 1.18.0,3. Mac
mysql:
image: mysql:5.6
container_name: app-db
environment:
MYSQL_ROOT_PASSWORD: ${MYSQL_ROOT_PASSWORD}
MYSQL_DATABASE: ${MYSQL_DATABASE}
MYSQL_USER: ${MYSQL_USER}
MYSQL_PASSWORD: ${MYSQL_PASSWORD}
healthcheck:
test: /usr/bin/mysql --host=127.0.0.1 --user=user --password=password --silent --execute \"SELECT 1;\"
interval: 30s
timeout: 10s
retries: 5
ports:
- "3306:3306"
volumes:
- mysql_data:/var/lib/mysql
networks:
- app
restart: always
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但我总是很快就会收到以下错误(几秒钟内)
docker-compose up
Creating network "compose_app" with the default driver
Creating app-db ... done
Creating app-db ...
ERROR: for app Container "bf94292aa4fa" is unhealthy.
ERROR: Encountered errors while bringing up the project.
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请帮忙。谢谢
我见过args.foreach(arg => println(arg)),但是当我搜索文档http://www.scala-lang.org/api/current/index.html#scala.Array时.我找不到它和它的伴随对象doc.
有什么建议?谢谢