我是通过Microsoft SQL Server数据工具,VS 2015自学SSRS.我从这里使用教程
我看不到我在预览中创建的参数.已在参数属性中选择了可见.我错过了什么?如果有人可以帮助我,请提前致谢.
.Microsoft SQL Server数据工具,VS 2015
.Microsoft SQL Server管理工作室2016
我的for循环太长了.作为演示,方法B有三个for循环.有没有办法可以将它减少为一个简短的for循环(一个循环)?谢谢
public class MyMates
{
private static TreeSet<String> myTable = new TreeSet<String>();
private static String[] names1 = null;
private static String[] names2 = null;
private static String[] names3 = null;
public MyMates()
{
super();
myTable = new TreeSet<String>();
}
public static String methodA(String aTemp)
{
String[] names1 = new String[] {"Amy", "Jose", "Jeremy", "Alice", "Patrick"};
String[] names2 = new String[] { "Alan", "Amy", "Jeremy", "Helen", "Alexi"};
String[] names3 = new String[] { "Adel", "Aaron", "Amy", "James", "Alice" };
return aTemp; …Run Code Online (Sandbox Code Playgroud) [RegularExpression(@"\S*[a-z\s]\S*\s*", ErrorMessage = "Please add
category name letters only")]
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如果我输入类似这样的单词,那么这很好用.测试测试.但是,如果我尝试这样做...测试测试,我将获得我实现的ErrorMessage.问题是我不知道最终用户会输入多少单词.有没有办法让无限制的空白到位?有人能告诉我怎么做吗?提前致谢.我正在使用VS2010
我关注http://www.mikesdotnetting.com/Article/125/ASP.NET-MVC-Uploading-and-Downloading-Files.在SQL Server 2008R2中使用带有ADO.NET的C#中的VS2010,ASP.NET 4.0,MVC3.我收到以下错误消息...
'System.Web.HttpPostedFileBase'不包含'HasFile'的定义,并且没有可以找到接受类型'System.Web.HttpPostedFileBase'的第一个参数的扩展方法'HasFile'(您是否缺少using指令或程序集引用?)
我搜索了Stackflow,有一些关于包括System.Web.Abstractions的内容.我包括了这个,我仍然得到错误.如果有人能告诉我解决方案,请提前感谢.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using System.IO;
using System.Data.SqlClient;
using System.Web.Helpers;
namespace MvcApplication1.Controllers
{
public class MyController : Controller
{
//
// GET: /My/
public ActionResult Index()
{
foreach (string upload in Request.Files)
{
if (!Request.Files[upload].HasFile()) continue;
string mimeType = Request.Files[upload].ContentType;
Stream fileStream = Request.Files[upload].InputStream;
string fileName = Path.GetFileName(Request.Files[upload].FileName);
int fileLength = Request.Files[upload].ContentLength;
byte[] fileData = new byte[fileLength];
fileStream.Read(fileData, 0, fileLength);
const string connect = @"Server=.\SQLExpress;Database=FileTest;Trusted_Connection=True;";
using …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用给定的名称和性别创建一个新的Couple实例,并在addCouple方法中添加到couple的集合.我有另一个名为Couple的课程.在那个课程中,我有一个名字和性别的getter和Setters.我尝试使用列表的批量操作:
List<Dating> list1 = new ArrayList<Dating>(this.addCouple);
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但我得到一个错误"非静态变量,这不能从静态上下文中引用".然后我尝试使用Collection.sort然后打印出列表.我收到了同样的错误消息.所以我相信我不知道如何使用this.addList.有人能告诉我如何使用它.我应该用this.addList吗?提前致谢.
public class Dating
{
private List<Male> maleList;
private List<Female> femaleList;
public Dating()
{
super();
maleList = new ArrayList<Single>();
femaleList = new ArrayList<Single>();
}
public void lists()
{
this.addList("Jack","Male",'m');
this.addList("Mike","Male",'m');
this.addList("Lynda","Female",'f');
this.addList("Katie","Female",'f');
}
public static void addCouple (String aName, char aGender)
{
Collections.sort(this.addList);
for (Couple group : this.addList)
{
System.out.println(" " + group.getName() + " " + group.getGender());
}
}
Run Code Online (Sandbox Code Playgroud) 有人可以善良并帮助我在这里.提前致谢...
我的代码在下面输出字符串作为重复.我不想使用Sets或ArrayList.我正在使用java.util.Random.我正在尝试编写一个代码来检查字符串是否已经被随机输出,如果是,那么它将不会显示.我哪里出错了,我该如何解决这个问题.
public class Worldcountries
{
private static Random nums = new Random();
private static String[] countries =
{
"America", "Candada", "Chile", "Argentina"
};
public static int Dice()
{
return (generator.nums.nextInt(6) + 1);
}
public String randomCounties()
{
String aTemp = " ";
int numOfTimes = Dice();
int dup = 0;
for(int i=0 ; i<numOfTimes; i++)
{
// I think it's in the if statement where I am going wrong.
if (!countries[i].equals(countries[i]))
{
i = i + 1;
}
else …Run Code Online (Sandbox Code Playgroud) 输出不按升序排序.这是我得到的代码和输出.
实际输出是:
Amy Jose Jeremy Alice Patrick Alan Amy Jeremy Helen Alexi
虽然预期产量是:
Amy, Alice, Jeremy, jose, Patrick Alan, Amy, Alexi, Helen, Jeremy
代码是:
public class MyFriends
{
static Set<String> names = new TreeSet<String>();
public MyFriends()
{
super();
names = new TreeSet<String>();
}
public static void exampleMethod()
{
String[] name1 = {"Amy", "Jose", "Jeremy", "Alice", "Patrick"};
String[] name2 = { "Alan", "Amy", "Jeremy", "Helen", "Alexi"};
for (int i = 0; i < name1.length; i++)
{
names.add(name1[i]);
}
for (String aString …Run Code Online (Sandbox Code Playgroud) pstrjds,从您提供的代码我试图实现该代码和几天前提供的msdn链接.我不知道如何把它放在一起,但我看到一条消息"已经声明了变量名''ID'.变量名在查询批处理或存储过程中必须是唯一的." 我是否需要创建存储过程?我可以假设我的ID位也正确,你解释了多少次?谢谢.在此处输入代码
cs.Open();
int remainingStock = 0;
string Query = "SELECT StockA SET QTY = @QTY " + "WHERE ID = @ID;";
SqlCommand cmd = new SqlCommand(Query, cs);
cmd.Parameters.Add("@ID", SqlDbType.Int);
cmd.Parameters["@ID"].Value = 1;
cmd.Parameters.AddWithValue("@ID", Query);
try
{
if (remainingStock == 1)
{
lbqty.Text = "Not enough stocks.";
}
else
{
cmd.CommandText = "UPDATE StockA SET QTY = QTY-1
WHERE ID=1";
int rowsUpdated = cmd.ExecuteNonQuery();
remainingStock--;
string remaining = "Remaining stocks: " +
remainingStock.ToString();
txQty.Text = remaining;
lbqty.Text = remaining;
DGA.Update(); …Run Code Online (Sandbox Code Playgroud)