我有2张桌子,
管理员,定价
我想做一个选择加入两个表,其中pricing.relation = admin.id
如何重命名value,id和date_created行,以便它们不会相互覆盖?
这是我正在尝试的事情:
$sub_types = $database->query('
SELECT
pricing.*,
admin.*
FROM
pricing,
admin
WHERE pricing.relation = admin.id
');
Run Code Online (Sandbox Code Playgroud) 我有一个列出时间表的视图.
在该视图中,每个时间表都有一个可交付的字段...我有一个DeliverableController,它有一个动作"DropdownList",它调用模型并获取可交付成果列表并将它们推送到可交付的视图(只创建一个下拉框) .
当我循环遍历我的时间表时,我想得到DeliverableController/DropdownList的响应,并把它放在我的可交付字段应该在时间表上.
到目前为止我的代码是:
DeliverableController:
class DeliverableController extends BaseController {
private $deliverableRepository;
function __Construct( IDeliverableRepository $deliverableRepo )
{
$this->deliverableRepository = $deliverableRepo;
}
...
public /* */ function DropdownList()
{
$deliverables = $this->deliverableRepository->Deliverables();
return View::make( 'Deliverable/_DropdownList', array( "Model" => $deliverables ) );
}
}
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Deliverables/_DropdownList查看:
<?php
foreach( $Model as $item )
{
?>
<select name="">
<option value = "<?php echo $item->ID; ?>"><?php echo $item->Title; ?></option>
</select>
<?php
}
?>
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时间表控制器:
class TimesheetController extends BaseController {
private …Run Code Online (Sandbox Code Playgroud) 我当前正在将命令行进程的输出渲染到文本框中。问题是,在正常的命令提示符窗口中,写入的其中一行有一个负载栏之类的东西......每隔几秒它就会输出一个“。” 到屏幕上......经过几个点后,它将开始一个新行,然后继续加载,直到完成其过程。
使用以下代码,而不是获取这些“。” 一个接一个地出现,我的OutputDataRecieved正在等待整行被写出...所以负载栏是无用的...即,它等待“........................”并且然后它对它起作用。
有没有一种方法可以跟踪输出到屏幕的每个字符而不是每行输出的字符?
//Create process
System.Diagnostics.Process process = new System.Diagnostics.Process();
// arguments.ProcessStartInfo contains the following declaration:
// ProcessStartInfo = new ProcessStartInfo( "Cmd.exe" )
// {
// WorkingDirectory = executableDirectoryName,
// UseShellExecute = false,
// RedirectStandardInput = true,
// RedirectStandardOutput = true,
// CreateNoWindow = true,
// }
process.StartInfo = arguments.ProcessStartInfo;
//Start the process
StringBuilder sb = new StringBuilder();
bool alreadyThrownExit = false;
// The following event only seems to be run per line output rather than each character …Run Code Online (Sandbox Code Playgroud) 我有以下方法GetCurrentUserDelayedTest,我想延迟.我在这里留下了原始实现GetCurrentUser来演示我最初是如何使用它的:
import { Injectable } from '@angular/core';
import { Observable, of } from 'rxjs';
import { User } from '../models/user';
export class UserService {
// Normal method without delay
public GetCurrentUser(): Observable<User>
{
return of(new User(""));
}
// Method with delay attempt at code
public GetCurrentUserDelayedTest(): Observable<User>
{
var observable = new Observable<User>((observable) => {
setTimeout(() => {
return observable.complete();
}, 2000);
});
observable.subscribe(() => {
return of(new User(""));
});
return observable;
}
}
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我试图延迟该方法将其数据返回2秒.
我究竟做错了什么?我是angular …
Dim stringIdCollection
stringIdCollection = Join( Request.Form( "id" ), "', '" ) )
Dim whereStatement
whereStatement = "WHERE id IN ('" & stringIdCollection & "');"
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我收到此错误:
Microsoft VBScript 编译错误“800a0401”
预计声明结束
/includes/Process.asp,第 49 行 stringIdCollection = Join( Request.Form( "id" ), "', '" ) ) --------------------- -------------------------------------------------- -^
是否可以在 Request.Form 上使用 Join ?
我希望输出是:
“哪里 ID 在('122','344','599')”
如何从视图模型中调用加载栏?凉爽的小点漂浮着.我似乎无法找到正确的Bing短语来搜索它.
我找不到User.Identity.Name来自哪个引用程序集.我怎么找到它?我需要将它添加到类库而不是我已经创建的默认MVC 5应用程序,以便我可以访问它吗?
http://msdn.microsoft.com/en-us/library/system.web.httpcontext.user(v=vs.110).aspx
C#类库/ AUser.cs
public class AUser
{
public string Username
{
get
{
return User.Identity.Name // doesn't notice User
}
}
}
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我正在将用户帐户迁移到最少需要6个字符的应用程序.
如果我运行以下功能
var result = await UserManager.CreateAsync(newUser, "");
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它会当然抱怨密码无效.有没有办法我可以暂时忽略密码要求,这样我就可以创建我的用户?
笔记:
private ApplicationUserManager _userManager;
public ApplicationUserManager UserManager
{
get
{
if (_userManager == null)
{
this._userManager = HttpContext.GetOwinContext().GetUserManager<ApplicationUserManager>();
}
return _userManager;
}
private set
{
_userManager = value;
}
}
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遗憾的是,这不起作用:
this._userManager.PasswordValidator = new PasswordValidator
{
RequiredLength = -1, // I've also tried 0
RequireNonLetterOrDigit = false,
RequireDigit = false,
RequireLowercase = false,
RequireUppercase = false,
};
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因为它声明"您的密码长度必须至少为-1个字符"
我该如何做到这一点?
@if(item.i % 2 == 0)
{
<div class="row">
}
@if(item.i % 2 == 0)
{
</div>
}
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没有它抱怨我没有完成标记,因此我认为我没有}在if语句的末尾添加
你如何访问子方法,例如?
class A
{
public function Start()
{
// Somehow call Run method on the B class that is inheriting this class
}
}
class B extends A
{
public function Run()
{
...
}
}
$b = new B();
$b->Start(); // Which then should call Run method
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join ×2
php ×2
angular ×1
asp-classic ×1
laravel ×1
mvvm ×1
mysql ×1
owin ×1
razor ×1
request.form ×1
typescript ×1