我试图在狮身人面像中为矩阵添加一些颜色。我以前使用过hf-tikz。但是,当我将其添加到Sphinx时,它会错误地呈现它。
我想要得到的结果是
我得到的结果是
这是我的代码。
main.rst:
.. math::
\left(\begin{array}{cc}
\tikzmarkin[style red]{a}a\tikzmarkend{a}
& \tikzmarkin[style green]{b}b\tikzmarkend{b} \\
\tikzmarkin[style blue]{c}c\tikzmarkend{c}
& \tikzmarkin[style orange]{d}d\tikzmarkend{d} \\
\end{array}\right)
\star
\left(\begin{array}{cc}
\tikzmarkin[style red]{w}w\tikzmarkend{w}
& \tikzmarkin[style green]{x}x\tikzmarkend{x} \\
\tikzmarkin[style blue]{y}y\tikzmarkend{y}
& \tikzmarkin[style orange]{z}z\tikzmarkend{z} \\
\end{array}\right)
=
\left(\begin{array}{cc}
\tikzmarkin[hor=style red]{aw}{a\star w}\tikzmarkend{aw}
& \tikzmarkin[hor=style green]{bx}b\star x\tikzmarkend{bx} \\
\tikzmarkin[hor=style blue]{cy}c\star y\tikzmarkend{cy}
& \tikzmarkin[hor=style orange]{dz}d\star z\tikzmarkend{dz} \\
\end{array}\right)
Run Code Online (Sandbox Code Playgroud)
conf.py
extensions = [
'sphinx.ext.imgmath',
]
# Math configurations (https://tex.stackexchange.com/a/69770/51173)
imgmath_image_format = 'svg'
imgmath_use_preview = True
imgmath_latex_preamble = r'''
\usepackage{xcolor}
\usepackage[customcolors]{hf-tikz}
\colorlet{myred}{red!50!purple!30} …Run Code Online (Sandbox Code Playgroud) 假设我知道每个点的距离,我尝试将2D点重新投影到其原始3D坐标。遵循OpenCV文档,我设法使其与零失真一起工作。但是,当存在变形时,结果将不正确。
因此,其想法是扭转以下情况:
分为以下内容:
通过:
cv::undistortPointsz反向标准化。f_x并f_y返回归一化的相机坐标(在测试时凭经验找到)?在下面的代码中,在第2步中,如果我不减去-即使未失真的结果也关闭了,#include <iostream>
#include <opencv2/calib3d/calib3d.hpp>
#include <opencv2/core/core.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <vector>
std::vector<cv::Point2d> Project(const std::vector<cv::Point3d>& points,
const cv::Mat& intrinsic,
const cv::Mat& distortion) {
std::vector<cv::Point2d> result;
if (!points.empty()) {
cv::projectPoints(points, cv::Mat(3, 1, CV_64F, cvScalar(0.)),
cv::Mat(3, 1, CV_64F, cvScalar(0.)), intrinsic,
distortion, result);
}
return result;
}
std::vector<cv::Point3d> Unproject(const std::vector<cv::Point2d>& points,
const std::vector<double>& Z,
const cv::Mat& intrinsic,
const cv::Mat& distortion) { …Run Code Online (Sandbox Code Playgroud) 我试图在同一个图中显示两个 OpenCV 视频源作为子图,但找不到如何做到这一点。当我尝试使用时plt.imshow(...), plt.show(),窗口甚至不会出现。当我尝试使用 时cv2.imshow(...),它显示两个独立的数字。我真正想要的是子图:(。有什么帮助吗?
这是我到目前为止的代码:
import numpy as np
import cv2
import matplotlib.pyplot as plt
cap = cv2.VideoCapture(0)
ret, frame = cap.read()
while(True):
ret, frame = cap.read()
channels = cv2.split(frame)
frame_merge = cv2.merge(channels)
#~ subplot(211), plt.imshow(frame)
#~ subplot(212), plt.imshow(frame_merged)
cv2.imshow('frame',frame)
cv2.imshow('frame merged', frame_merge)
k = cv2.waitKey(30) & 0xff
if k == 27:
break
cap.release()
cv2.destroyAllWindows()
Run Code Online (Sandbox Code Playgroud)
更新:理想情况下,输出应该类似于:
我正在尝试为我的GIT创建一个看起来像这样的别名:
[alias]
send = !git add . && git commit -m "AUTOCOMMIT: $(date)" && git push
Run Code Online (Sandbox Code Playgroud)
此别名适用于不需要任何消息的微小修改.问题是每当我运行git send它时返回以下内容:
$ git send
error: pathspec 'Fri' did not match any file(s) known to git.
error: pathspec 'Aug' did not match any file(s) known to git.
error: pathspec '22' did not match any file(s) known to git.
error: pathspec '11:31:18' did not match any file(s) known to git.
error: pathspec 'PDT' did not match any file(s) known to git.
error: pathspec …Run Code Online (Sandbox Code Playgroud) 我的问题是为什么我需要取消引用并引用以下代码的指针才能工作?不参考/反对取消吗?我真的很感激,如果有人能解释它,就像我五岁:)
码:
template <typename T>
class binNode {
private:
T key;
public:
binNode * left;
binNode * right;
binNode * parent;
binNode() {
this->left = NULL;
this->right = NULL;
this->parent = NULL;
}
// arg constructor:
binNode (T key) {
this->key = key;
this->left = NULL;
this->right = NULL;
this->parent = NULL;
}
T getKey() {
return this->key;
}
void setKey(T key) {
this->key = key;
}
};
template<typename T> class Tree {
private:
binNode <T> *root;
public:
Tree() { …Run Code Online (Sandbox Code Playgroud) c++ ×2
opencv ×2
python ×2
alias ×1
binary-tree ×1
dereference ×1
git ×1
git-config ×1
latex ×1
matplotlib ×1
pointers ×1
projection ×1
reference ×1
subplot ×1
tikz ×1