小编Ami*_*hal的帖子

我通过ajax获取特定的产品项列表,方法是将它们的唯一ID传递给服务器.现在每个产品都有自己的一组属性,我必须在页面上显示产品图像.当我通过jquery设置值时,只打印了数组中的最后一个值.以下是我的编码文件.

images.php

while($fetch = mysql_fetch_array($result))
      {
      ?>

      <div class="col-sm-4">
       <div class="thumbnail">

        <a class="productitemid" href="productpurchase.php?id=<?php echo $fetch['itemID'];?>"><img class="img-responsive productimage" src="uploadedfiles\<?php echo $fetch['imageURL'];?>" alt="<?php echo $fetch['imageURL'];?>" /></a>

        <div class="text-center productitemname" style="font-weight:bold;"><?php echo $fetch['itemName']; ?></div>
        <div class="badge col-sm-offset-1 productprice"><?php echo $fetch['price']; ?></div>
        <span class="col-md-offset-7"><a class="productitemid btn btn-success" href="productpurchase.php?id=<?php echo $fetch['itemID'];?>">BUY</a></span>

       </div>
      </div>
      <?php
      }

js文件

$(document).ready(function(){
  $('.menProdCatgry').on('click',function(){
   $.ajax({
    type: "post",
    url: "getselectedproducts.php",
    data:{
     "prodId" : $('.menProdCatgry').attr('prodCatId')
    },
    dataType: "json",
    success: function(data){
     console.log(data);
     $.each(data, function(){
     var getprodId = this.prodId;
     var getimageURL = this.imageURL;
     var …

我刚开始在 php 中学习 OOPS。我写了一个简单的程序来实现继承。当不在对象上下文中时，我收到 $this 的致命错误。谁能解释一下这个错误，这是什么意思？这是我的代码：

<?php

    class human{

        public $gender;

        public function _construct($gender)
        {
            $this->gender=$gender;

            echo $this->get_gender();
        }

        public function get_gender()
        {
            return $this->gender;
        }


    }

    class person extends human{

        public $name;
        public $surname;

        public static function set_name($name)
        {
            $this->name=$name;
        }
        public static function set_surname($surname)
        {
            $this->surname=$surname;
        }

        public static function get_name()
        {
            return $this->name;
        }
        public static function get_surname()
        {
            return $this->surname;
        }
    }

    $john = new person('male');
    $john->set_name('John');
    $john->set_surname('Williams');
    echo $john->get_name().' '.$john->get_surname().'is a '.$john->get_gender();
    ?>

我从sql server获取季度记录.这些记录就像每年每个季度的总借记和贷记.在我的SQL查询中,我已经制作了季度,并且年份是动态的,您可以在代码中看到.

public List<QuarterlyExpenseList> GetExpenseDataQuarterly(string Id, string Year)
        {
            string SQL = "select aspnetusers.username, SUM(case when Expense.Type='credit' and (Expense.Date>='@year-01-01' and Expense.Date<='@year-03-31') then Expense.Amount else 0 end) as QuarterOneCredits,";
            SQL += " SUM(case when Expense.Type='credit' and (Expense.Date>='@year-04-01' and Expense.Date<='@year-06-30') then Expense.Amount else 0 end) as QuarterTwoCredits,";
            SQL += " SUM(case when Expense.Type='credit' and (Expense.Date>='@year-07-01' and Expense.Date<='@year-09-30') then Expense.Amount else 0 end) as QuarterThreeCredits,";
            SQL += " SUM(case when Expense.Type='credit' and (Expense.Date>='@year-10-01' and Expense.Date<='@year-12-31') then Expense.Amount else 0 end) as QuarterFourCredits,";
            SQL …

我正在阅读有关脚本语言和编程语言之间的区别，有一点是，脚本语言在客户端计算机上运行，​​而诸如c＃，vb，java和php等编程语言则在服务器计算机上运行。但是php被认为是一种脚本语言。现在，这令人困惑！我们通常使用php编写在服务器上运行的代码，那么php如何成为脚本语言？