我的网络应用程序出现了问题.这是我的代码:
@app.route('/addrec',methods = ['POST', 'GET'])
def addrec():
if g.user:
if request.method == 'POST':
#UPPER PANE
payor = request.form['payor']
receiptno = request.form['OR']
paymentmethod = request.form['paymentmethod']
naive_dt = time.strftime("%m/%d/%Y")
collectiondate = naive_dt = datetime.now()
message = request.form['message']
#LOWER PANE
url_to_scrape = 'http://localhost:5000/form'
r = requests.get(url_to_scrape)
soup = BeautifulSoup(r.text)
nature = []
for table_row in soup.select("table.inmatesList tr"):
cells = table_row.findAll('td')
if len(cells) > 0:
nature = cells[0].text.strip()
natureamt = cells[1].text.strip()
nature = {'nature': nature, 'nature': natureamt}
nature_list.append(nature)
ent = Entry(receiptno, payor,officer, paymentmethod, collectiondate,message, …Run Code Online (Sandbox Code Playgroud) 嗨,我想在haskell中定义一个main函数,类似于java中的main函数
main :: String -> IO()
main args = do
putStrLn args
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但是当我尝试运行程序时,这会给我一个错误.
我在教科书中发现了一个没有答案的问题.
"找到两个非空字符串a和b,这样a ^ b = b ^ a.通常可以说一对那些通勤字符串?"
我能想到的唯一字符串是a和b是否相同,如"aaa"或"apa".答案很容易还是更复杂?
什么是(^)的类型?如果我只是在utop中输入(^)我得到"bytes - > bytes - > bytes ="但是我猜这个类型必须是String?
我哪里错了?
我正在关注本教程:https://www.youtube.com/watch ?v=PvrnbhGeSKE
但是,当我粘贴代码时,Eclipse 给出了这个错误:“ALIGN_CENTER 无法解析或不是字段”
package main;
import entities.*;
import dao.*;
import java.util.*;
import org.apache.poi.hssf.usermodel.*;
import org.apache.poi.hssf.util.*;
import org.apache.poi.ss.usermodel.*;
import org.apache.poi.ss.util.*;
public class Main {
public static void main(String[] args) {
try {
ProductModel pmodel = new ProductModel();
HSSFWorkbook workbook = new HSSFWorkbook();
HSSFSheet sheet = workbook.createSheet("List Products");
Row rowheading = sheet.createRow(0);
rowheading.createCell(0).setCellValue("Id");
rowheading.createCell(1).setCellValue("Name");
rowheading.createCell(2).setCellValue("Creation Date");
rowheading.createCell(3).setCellValue("Price");
rowheading.createCell(4).setCellValue("Quantity");
rowheading.createCell(5).setCellValue("Sub Total");
for (int i = 0; i < 6; i++) {
CellStyle stylerowHeading = workbook.createCellStyle();
Font font = workbook.createFont(); …Run Code Online (Sandbox Code Playgroud) apache-poi ×1
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