我想知道一些基于用户输入动态创建表的方法(SQL Prepared Statement)
CREATE TABLE ? (
First_Name char(50),
Last_Name char(50)
)
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我应该用什么来代替问号
我正在尝试为if-else类型结构创建一个非常简单的解析器,它将构建并执行SQL语句.
我不是测试执行语句的条件,而是测试构建字符串的条件.
一个例子是:
select column1
from
#if(VariableA = Case1)
table1
#else if(VariableA = Case2)
table2
#else
defaultTable
#end
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如果VariableA等于Case1,则结果字符串应为: select column1 from table1
一个更复杂的例子是嵌套的if语句:
select column1
from
#if(VariableA = Case1)
#if(VariableB = Case3)
table3
#else
table4
#else if(VariableA = Case2)
table2
#else
defaultTable
#end
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这是我真正遇到麻烦的地方,我想不出一个正确识别每个if-else-end组的好方法.
另外,我不知道有什么好方法可以跟踪"else"子句中的字符串是否应该评估为true.
我一直在网上寻找不同类型的解析算法,所有这些算法看起来都非常抽象和复杂.
对于这个非计算机科学专业,有什么建议吗?
我从另一个问题中找到了这段代码
private void updateLine(String toUpdate, String updated) throws IOException {
BufferedReader file = new BufferedReader(new FileReader(data));
String line;
String input = "";
while ((line = file.readLine()) != null)
input += line + "\n";
input = input.replace(toUpdate, updated);
FileOutputStream os = new FileOutputStream(data);
os.write(input.getBytes());
file.close();
os.close();
}
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在我替换一些行之前,这是我的文件
example1
example2
example3
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但是当我替换一行时,该文件现在看起来像这样
example1example2example3
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这使得当文件中有很多行时无法读取文件.
我将如何编辑上面的代码,使我的文件在开始时看起来像什么?
我正在使用GET方法从url中检索值,然后使用if语句确定它们是否存在,然后针对数据库查询它们以仅显示与它们匹配的项目,我的请求会出现未知错误.这是我的代码
$province = $_GET['province'];
$city = $_GET['city'];
if(isset($province) && isset($city) ) {
$results3 = mysql_query("SELECT *
FROM generalinfo
WHERE province = $province
AND city = $city ")
or die( "An unknown error occurred with your request");
} else {
$results3 = mysql_query("SELECT * FROM generalinfo");
} /*if statement ends*/
Run Code Online (Sandbox Code Playgroud) 我正在尝试执行以下SQL 2008代码,它说"="和"else"附近有一个问题...我无法理解代码有什么问题
ALTER PROCEDURE dbo.LoginEmp @username NVARCHAR(10),
@password NVARCHAR(10),
@confirm INT output,
@emp_name NVARCHAR(50) output,
@emp_id BIGINT output
AS
IF EXISTS (SELECT @emp_id = emp_id,
@emp_name = emp_name_ara
FROM Employee
WHERE ( emp_username LIKE @username
AND emp_password LIKE @password ))
BEGIN
SET @confirm=1
INSERT INTO EmployeeLog
(log_emp_id,
log_act_id,
log_date,
log_data)
VALUES (@emp_id,
1,
GETDATE(),
-1)
END
ELSE
BEGIN
SET @confirm=0
END
RETURN
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这个陈述相当于
x++;
System.out.println(info + ": " + x);
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和
System.out.println(info + ": " + x++);
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相当于
System.out.println(info + ": " + x);
x++;
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由于JVM一次只能处理一个语句,它是否会像这样划分这些语句?
我想改变CPU频率。我已经安装了 cpufrequtils。命令“ cpufreq-info
”给我信息
cpufrequtils 008: cpufreq-info (C) Dominik Brodowski 2004-2009
Report errors and bugs to cpufreq@vger.kernel.org, please.
analyzing CPU 0:
driver: intel_pstate
CPUs which run at the same hardware frequency: 0
CPUs which need to have their frequency coordinated by software: 0
maximum transition latency: 0.97 ms.
hardware limits: 1.20 GHz - 2.40 GHz
available cpufreq governors: performance, powersave
current policy: frequency should be within 1.20 GHz and 2.40 GHz.
The governor "performance" may decide which speed to use …
Run Code Online (Sandbox Code Playgroud) 我试图在angularjs.org的angular-phonecat中完成教程.在stetp三中我用量角器进行端到端测试时出错.这是错误代码.
Using ChromeDriver directly...
Cannot read property 'matcherFn_' of undefined
[launcher] Runner Process Exited With Error Code: 1
npm ERR! angular-phonecat@0.0.0 protractor: `protractor test/protractor-conf.js`
npm ERR! Exit status 1
npm ERR!
npm ERR! Failed at the angular-phonecat@0.0.0 protractor script.
npm ERR! This is most likely a problem with the angular-phonecat package,
npm ERR! not with npm itself.
npm ERR! Tell the author that this fails on your system:
npm ERR! protractor test/protractor-conf.js
npm ERR! You can get their info via: …
Run Code Online (Sandbox Code Playgroud) 我正在使用StringUtils.abbreviateMiddle(string, middle, targetLength);
缩写中间的字符串,但使用此方法切断了单词.有没有一种方法,它只会在最接近弦的中间位置的空间切断弦?
public static String shortenStringMiddle(String string, String middle, int targetLength) {
targetLength = Math.abs(targetLength);
if (string != null && string.length() > targetLength) {
return StringUtils.abbreviateMiddle(string, middle, targetLength);
}
else {
return string;
}
}
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输入如果应用于此文本:
东南亚鱼虾养殖的疾病控制 - 诊断和畜牧技术:SEAFDEC-OIE研讨会论文集 - 东南亚鱼虾养殖疾病控制研讨会 - 诊断和畜牧技术,2001年12月4日至6日,伊洛伊洛市,菲律宾
System.out.println(StringUtils.abbreviateMiddle("Disease Control in Fish and Shrimp Aquaculture in Southeast Asia - Diagnosis and Husbandry Techniques: Proceedings of the SEAFDEC-OIE Seminar-Workshop on Disease Control in Fish and Shrimp Aquaculture in Southeast Asia - Diagnosis and …
Run Code Online (Sandbox Code Playgroud) 根据ECMAScript 规范,Javascript 数值对应于双精度 64 位二进制格式 IEEE 754 值。
\n\n对于我目前正在开发的 WebIDL 验证器,我需要能够弄清楚给定的数值是否可以转换为WebIDL 浮点类型,即它是否可以表示为有限单精度 32 位 IEEE 754价值。
\n\n我目前决定采用以下方法:
\n\nvalidate: function(value) {\n if (typeof value !== \'number\' || !Number.isFinite(value)) {\n return false;\n }\n\n if (value === 0) {\n return true;\n }\n\n var view = new DataView(new ArrayBuffer(4));\n\n view.setFloat32(0, value);\n\n var converted = view.getFloat32(0);\n var relativeError = Math.abs(value - converted) / value;\n\n return relativeError < Number.EPSILON;\n}\n
Run Code Online (Sandbox Code Playgroud)\n\n本质上,我正在做的是:
\n\nDataView
在 4 …javascript floating-point ieee-754 webidl floating-point-conversion