小编use*_*251的帖子

我有一个功能来执行cron作业

def add_config_job(sched, job):

    module = JOB_METHODS.get(job["type"])
    if module is None:
        logging.warn("job type %r not supported", job["type"])
        return

    func = module.cron_job
    args = (job,)
    name = "%s__%s" % (job["name"], job["id"])
    start_date = job.get("start_date")
    run_at = job["run_at"]

    if isinstance(job["run_at"], dict):
        sched.add_cron_job(func, args=args, name=name, start_date=start_date,
                           **run_at)
    elif isinstance(job["run_at"], basestring):
        sched.add_date_job(func, args=args, name=name, date=run_at)
    else:
        logging.warn("unsupported 'run_at' type (%s given)", run_at)

我得到错误，因为错过了几秒钟的工作

2015-05-14_00:00:02.76629 WARNING: Run time of job "Daily VPN Connexion__1 (trigger: cron[day='*', hour='0', minute='0', second='0'], next run at: 2015-05-14 00:00:00)" was missed …

我已经浏览了这个网站.从这里我得到了使用cudamallocHost的固定内存提供了比cudamalloc更好的性能.然后我使用两个不同的简单程序并测试执行时间为

使用cudaMallocHost

#include <stdio.h>
#include <cuda.h>

// Kernel that executes on the CUDA device
__global__ void square_array(float *a, int N)
{
  int idx = blockIdx.x * blockDim.x + threadIdx.x;
  if (idx<N) a[idx] = a[idx] * a[idx];
}

// main routine that executes on the host
int main(void)
{
    clock_t start;
    start=clock();/* Line 8 */
    clock_t finish;
  float *a_h, *a_d;  // Pointer to host & device arrays
  const int N = 100000;  // Number of elements in arrays
  size_t …

我有一个简单的程序，如 demo_use.c

#include "libhello.h"

int main(void) {
 hello();
 return 0;
}

libhello.h

void hello(void);

libhello.c

#include <stdio.h>

void hello(void) {
  printf("Hello, library world.\n");
}

我已经在终端中使用了命令

gcc demo_use.c -o test

错误 体系结构x86_64的未定义符号：“ _ hello”，

引用自：ccZdSQP3.o中的_main

ld：找不到架构x86_64的符号collect2：ld返回1退出状态