小编Jac*_*ack的帖子

我有一点问题.当我写这个for循环时,if.getAnswerScore().get(i)....中的变量带有错误消息的下划线: - 我在封闭范围内定义的局部变量必须是最终的或有效的最终.这与流有关吗？也许流不能用于循环？

for (int i = 0; i < 10; i++) {
    correct = active.stream()
        .filter(f -> f.getAnswerScore().get(i).getStatus().equals(AnswerStatus.ANSWERED_CORRECT))
        .count();
}

我想当时读取二进制文件字节，然后将该字节的位存储到整数数组中。同样，我想将 1 和 0（其中 8 个）的整数数组作为字节写入二进制文件？

当我点击我的按钮时,我的应用程序崩溃了.在log cat中它说我不能parseint""(没有)

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.fragment_main); 



    ocjena1 = (EditText) findViewById(R.id.ocjena1);
    ocjena2 = (EditText) findViewById(R.id.ocjena2);
    ocjena3 = (EditText) findViewById(R.id.ocjena3);
    ocjena4 = (EditText) findViewById(R.id.ocjena4);
    ocjena5 = (EditText) findViewById(R.id.ocjena5);
    ocjena6 = (EditText) findViewById(R.id.ocjena6);
    ocjena7 = (EditText) findViewById(R.id.ocjena7);
    ocjena8 = (EditText) findViewById(R.id.ocjena8);
    ocjena9 = (EditText) findViewById(R.id.ocjena9);
    ocjena10 = (EditText) findViewById(R.id.ocjena10);
    ocjena11 = (EditText) findViewById(R.id.ocjena11);
    ocjena12 = (EditText) findViewById(R.id.ocjena12);
    ocjena13 = (EditText) findViewById(R.id.ocjena13);
    ocjena14 = (EditText) findViewById(R.id.ocjena14);
    ocjena15 = (EditText) findViewById(R.id.ocjena15);
    ocjena16 = (EditText) findViewById(R.id.ocjena16);
    ocjena17 = (EditText) findViewById(R.id.ocjena17);
    ocjena18 = …