我想找出 XML 代码的 XPath 查询,其中city嵌套了要检查条件(是否等于“New York”)的元素 ie,并且bprice未嵌套所需的元素 ie。
这是 XML 代码:
<book>
<btitle>The Inferno</btitle>
<bprice currency = "dollars">19.99</bprice>
<bdate>2013-05-14</bdate>
<authorinfo>
<lastname>Brown</lastname>
<midname>G.</midname>
<firstname>Dan</firstname>
</authorinfo>
<publisherinfo>
<publishername>Doubleday</publishername>
<street>1745 Broadway</street>
<city>New York</city>
<zip>11119</zip>
<country>USA</country>
</publisherinfo>
</book>
Run Code Online (Sandbox Code Playgroud) mouseleave事件能够进行CSS更改,但是当ALT释放密钥时,keyup事件不会执行它应该进行的CSS更改.它干扰了mouseenter吗?如果是,那么如何解决问题?
$(document).on('mouseleave', '.el', function(e) {
$(this).css("background-color", "white");
$(this).css("color", "black");
});
$(document).on('keyup', '.el', function(e) {
if (e.altKey) {
$(this).css("background-color", "white");
$(this).css("color", "black");
}
});
$(document).on('mouseenter keypress', '.el', function(e) {
if (e.altKey) {
$(this).css("background-color", "#99DCFC");
$(this).css("color", "red");
}
});Run Code Online (Sandbox Code Playgroud)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table id="t1" align="center" border=1>
<tr>
<th>First Name</th>
<th>Last Name</th>
<th>Email Address</th>
<th>Telephone Number</th>
</tr>
<tr id="r">
<tbody>
<td id="d1" class="el" contenteditable="true"></td>
<td id="d2" class="el" contenteditable="true"></td>
<td id="d3" class="el" contenteditable="true"></td>
<td id="d4" class="el" contenteditable="true"></td>
<td>
<button id="del1">Delete</button>
</td>
</tbody>
</tr> …Run Code Online (Sandbox Code Playgroud)如果有两个表:
table1具有属性a1, a2, a3和table2具有属性b1, b2, b3。和a1是b1它们各自的主键。当对两个表应用自然联接时,新的主键是什么。合并 a1, b1形成复合主键,否则它们将成为两个单独的候选键
我正在尝试从数据库中删除数据,当从JTable中选择一行并BtnDelete1单击该按钮时.该操作应删除不同表中的行.但是当我单击删除按钮时,所有表中的选定行将被删除,除了"EMAIL_ADDRESSES"表,其中所有行都将被删除.
这是我删除fnumber给定行的存储过程:
CREATE DEFINER=`root`@`localhost` PROCEDURE `delete_contact`(IN fnumber int(2))
BEGIN
DELETE FROM PHONE_NUMBERS
WHERE F_number = fnumber;
DELETE FROM PHYSICAL_ADDRESS
WHERE F_number = fnumber;
DELETE FROM EMAIL_ADDRESSES
WHERE FNumber = fnumber;
DELETE FROM APPOINTMENTS
WHERE Fr_No = fnumber;
DELETE FROM FRIEND
WHERE F_no = fnumber;
END
Run Code Online (Sandbox Code Playgroud)
这是我的按钮BtnDelete1代码:
public class BtnDelete1 extends AbstractAction {
private FirstSwingApp mainGui;
public BtnDelete1(FirstSwingApp mainGui) {
super("Press Me");
putValue(MNEMONIC_KEY, KeyEvent.VK_P);
this.mainGui = mainGui;
}
public void actionPerformed(ActionEvent e) {
Object cell …Run Code Online (Sandbox Code Playgroud)