嗨,我想制作一个依赖于其他多项任务的木偶资源/任务.
例如:
file{'~/foo':}
file{'~/bar':}
file{'~/foobar':
require => File['~foo'],
require => File['~bar']
}
定义它的正确语法是什么？
谢谢
我在MS Team Foundation Server上作为特定用户进行身份验证时遇到问题.在旧版本中,它看起来像:
teamFoundationCredential = new System.Net.NetworkCredential("<USERNAME>", "<PASSWORD>", "<DOMAIN>");
TeamFoundationServer tfs = new TeamFoundationServer("http://mars:8080/", teamFoundationCredential);
有人可以告诉我2010版本的等效产品.到目前为止,我有:
ICredentialsProvider cred = null;
tfs = TfsTeamProjectCollectionFactory.GetTeamProjectCollection(new Uri("http://asebeast.cpsc.ucalgar.ca:8080/tfs/DefualtCollection"));
tfs.EnsureAuthenticated();
谢谢
在执行类型推断时,Haskell似乎无法解析'g == [a]'.任何想法如何使这项工作？
谢谢
module X where
import Control.Monad.State.Lazy
class Generator g where
next :: State g a
instance Generator ([] a) where
next = nextL
nextL :: State [a] a
nextL = state $ split
split :: [a] -> (a, [a])
split l = (head l, tail l)
我可以通过以下方式成功创建迭代路径:
var commonservice = collection.GetService<ICommonStructureService>();
// create new area path and iteration path
var iterationRoot = commonservice.GetNodeFromPath("\\MyTeamProject\\Iteration");
var newIterationPath = commonservice.CreateNode("my new sprint", iterationRoot.Uri);
但是,当我尝试将此路径分配给工作项并保存时,该字段不会验证.
如果我再次运行测试(已经创建了迭代),则相同的代码成功.
有人知道如何使这项工作？
谁能解释这个错误:
实例头中的语法错误(预期的构造函数)
class Nullable v where
default_val :: v
instance Num a => Nullable a where -- error reported here
default_val = 0::a
谢谢