小编use*_*473的帖子

我试图模拟SQL Server上的死锁.

_|worker_id|salary|
1|1        |100   |
2|2        |300   |

交易1在5秒内完成.

/* TRANSACTION 1*/
Use dbmcw;

DECLARE @sal1 INT, @sal2 int;

BEGIN TRAN;

SELECT @sal1 = salary
FROM dbo.deadlock_demonstration WITH(UPDLOCK) 
WHERE worker_id = 1;

WAITFOR DELAY '00:00:05.000';

SELECT @sal2 = salary
FROM dbo.deadlock_demonstration WITH(UPDLOCK)
WHERE worker_id = 2;

COMMIT TRAN;

交易2在3秒内完成.

/* TRANSACTION 2*/
Use dbmcw;

DECLARE @sal1 INT, @sal2 int;

BEGIN TRAN;

SELECT @sal2 = salary
FROM dbo.deadlock_demonstration WITH(UPDLOCK)
WHERE worker_id = 2;

SELECT @sal1 = salary
FROM dbo.deadlock_demonstration WITH(UPDLOCK) …

我是PostgreSQL的新手.我想为这个时间表模拟死锁:

如何在PostgreSQL中模拟死锁？有可能吗？如何锁定特定列？
编辑:

    BEGIN;
UPDATE deadlock_demonstration
SET salary1=(SELECT salary1 
FROM deadlock_demonstration
WHERE worker_id = 1 
FOR UPDATE)+100
WHERE worker_id=1;
SELECT pg_sleep(5);
commit;
SELECT salary2 FROM deadlock_demonstration WHERE worker_id = 1 FOR UPDATE;

在另一个屏幕中,我已经运行了这个

    BEGIN;
UPDATE deadlock_demonstration
SET salary2=(SELECT salary1 
FROM deadlock_demonstration
WHERE worker_id = 1
FOR UPDATE)+200
WHERE worker_id=1;
SELECT pg_sleep(5);
commit;
SELECT salary1 FROM deadlock_demonstration WHERE worker_id = 1 FOR UPDATE;

为什么没有发生死锁？你能给出一个建议,我应该改变什么来刺激僵局？