小编Blu*_*tle的帖子

这是我的情况:

    private CancellationTokenSource cancellationTokenSource;
    private CancellationToken cancellationToken;

    public IoTHub()
    {
        cancellationTokenSource = new CancellationTokenSource();
        cancellationToken = cancellationTokenSource.Token;

        receive();
    }

    private void receive()
    {
        eventHubClient = EventHubClient.CreateFromConnectionString(connectionString, iotHubD2cEndpoint);
        var d2cPartitions = eventHubClient.GetRuntimeInformation().PartitionIds;

        foreach (string partition in d2cPartitions)
        {
            ReceiveMessagesFromDeviceAsync(partition, cancellationToken);
        }
    }

    private async Task ReceiveMessagesFromDeviceAsync(CancellationToken ct)
    {
        var eventHubReceiver = eventHubClient.GetDefaultConsumerGroup().CreateReceiver(partition, DateTime.UtcNow);

        while (true)
        {
            if(ct.IsCancellationRequested)
            {
                break;
            }

            EventData eventData = await eventHubReceiver.ReceiveAsync();
            if (eventData == null) continue;

            string data = Encoding.UTF8.GetString(eventData.GetBytes());

            // Javascript function with Websocket
            Clients.All.setMessage(data);
        } …

我想计算开始时间和结束时间之间的差异.在HH:mm格式.

例如,当开始时间22.00和结束时间是1.00第二天时,我会收到负值.

如何让程序知道第二天的结束时间？

我的剧本:

public void setBeginTijd()
{
    String dateStart = "22:00";
    String dateEnd = "1:00";

    SimpleDateFormat format = new SimpleDateFormat("HH:mm");

    Date d1 = null;
    Date d2 = null;

    try
    {
        d1 = format.parse(dateStart);
        d2 = format.parse(dateEnd);

        long diff = d2.getTime() - d1.getTime();
        long diffMinutes = diff / (60 * 1000) % 60;
        long diffHours = diff / (60 * 60 * 1000) % 24;

        System.out.println(diffMinutes);
        System.out.println(diffHours);
    }
    catch (Exception e)
    {
        e.printStackTrace();
    } …