label.font.pointSize 是只读的,所以我不知道如何改变它.
我想删除屏幕顶部的状态栏.
这不起作用:
func application
(application: UIApplication,
didFinishLaunchingWithOptions launchOptions: NSDictionary?)
-> Bool
{
application.statusBarHidden = true
return true
}
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我也尝试过:
func application
(application: UIApplication,
didFinishLaunchingWithOptions launchOptions: NSDictionary?)
-> Bool
{
self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
var controller = UIViewController()
application.statusBarHidden = true
controller.setNeedsStatusBarAppearanceUpdate()
var view = UIView(frame: CGRectMake(0, 0, 320, 568))
view.backgroundColor = UIColor.redColor()
controller.view = view
var label = UILabel(frame: CGRectMake(0, 0, 200, 21))
label.center = CGPointMake(160, 284)
label.textAlignment = NSTextAlignment.Center
label.text = "Hello World"
controller.view.addSubview(label)
self.window!.rootViewController = controller
self.window!.makeKeyAndVisible()
return …Run Code Online (Sandbox Code Playgroud) 我想要一个与流相当的:
public static <T extends Number> T getSum(final Map<String, T> data) {
T sum = 0;
for (String key: data.keySet())
sum += data.get(key);
return sum;
}
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这段代码实际上并没有编译,因为0不能分配给类型T,但你明白了.
当我使用:normal命令(:normal i)进入插入模式时,如何退出插入模式?
如果我按<Esc>,或<cc>,或<c - [>,VIM退出命令模式,我无法运行my:normal命令.
我输入imap <c-e> <Esc>了我的.vimrc但是当我在命令模式下输入<ce>时,没有插入任何东西.我无法弄清楚如何在命令模式下输入"控制e".
例如,<co>工作,:normal Ihello<c-o>Aworld但有时我想在正常模式下执行多个命令.
我知道我可以使用宏,但我想知道如何使用:正常.
我正在尝试使用此代码,并将这些指令用于执行直接消息.发布正常的推文工作得非常好,但是当我尝试发送直接消息时,我得到了406.
这是完整的代码:
ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
// Request access from the user to access their Twitter account
[account requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error) {
// Did user allow us access?
if (granted == YES)
{
// Populate array with all available Twitter accounts
NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];
// Sanity check
if ([arrayOfAccounts count] > 0)
{
// Keep it simple, use the first account available
ACAccount *acct = …Run Code Online (Sandbox Code Playgroud) Rust 中的tap()等价物是什么?
它对迭代器中的每个项目调用一个函数map(),但不是传递函数返回的值,而是tap()返回原始项目。
例如,我想以println!()某种方式在流中调用:
foo.into_iter()
.filter(|x| x == target)
.tap(|x| println!("{:?}", x)) // <-- what goes here?
.map(|c| c.result)
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更正:
tap()在整个迭代器上调用一次闭包
inspect()在迭代器中的每个项目上调用闭包
try:
recursive_function()
except RuntimeError e:
# is this a max. recursion depth exceeded exception?
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如何判断何时达到最大递归深度?
我正在使用这里的说明来检测iOS 5设备上的Twitter框架.问题是旧设备没有Twitter库,所以我在iOS 4上收到以下错误:
dyld: Library not loaded: /System/Library/Frameworks/Twitter.framework/Twitter
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如何创建一个可以在iOS 5上使用Twitter框架并在iOS 4及更低版本上使用不同API的应用程序?
收到StopIteration异常后,如何关闭此服务器?sys.exit()不起作用.
#!/usr/bin/env python
from BaseHTTPServer import BaseHTTPRequestHandler,HTTPServer
PORT_NUMBER = 2000
from itertools import islice
filename = 'data/all.txt'
file = open(filename, 'r')
lines_gen = islice(file, None)
class MyHandler(BaseHTTPRequestHandler):
def do_GET(self):
global lines_gen
self.send_response(200)
self.send_header('Content-type','text/plain')
self.end_headers()
try:
for i in range(10):
next_line = lines_gen.next()
self.wfile.write(next_line)
except StopIteration:
# return response and shutdown the server
# ?????
return
try:
server = HTTPServer(('', PORT_NUMBER), MyHandler)
print('Started httpserver on port ' , PORT_NUMBER)
server.serve_forever()
except KeyboardInterrupt:
print('^C received, shutting down the web server')
server.socket.close()
Run Code Online (Sandbox Code Playgroud) Map如何与字典/对象不同?
换句话说,let x = {}和之间有什么区别let x = new Map()?
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